Oracle SQL PIVOT表 [英] Oracle SQL PIVOT Table

查看:83
本文介绍了Oracle SQL PIVOT表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我所拥有的是一个查询,可以在其中选择位置,数量等. 这是我的查询:而且,我正在尝试基本PIVOT我相信的表.我已经研究过PIVOT之类的东西,但是似乎没有明确的方法可以做到这一点.如果可以提供任何帮助,将不胜感激.

What I have is a query, where I am selecting locations, counts, etc. Here is my query: And, I am trying to basically PIVOT the tables I believe. I have looked into PIVOT and such, but it doesn't seem like there is a clear cut way to do it. If any help can be guided would be greatly appreciated.

更新后的查询包含类型和MT0建议

 WITH qry AS (
select Floor, 
"Mod", 
Count_Type, 
Remaining_Counts, 
Location, 
Floor || '' || "Mod" || '' || Count_Type || '' ||  Location as "Unique"
from
(
select bin_level as Floor, bin_module as "Mod", icqa_process_properties.icqa_process_property_value as Count_Type, count(icqa_processes.icqa_process_id) as Remaining_Counts, 
CASE when bin_type_name = '14-KIVA-DEEP' then ('KIVA-SHELF')  
     when bin_type_name = '18-KIVA-DEEP' then ('KIVA-SHELF')
     when bin_type_name = '24-KIVA-DEEP' then ('KIVA-SHELF')
     when bin_type_name = '30-KIVA-DEEP' then ('KIVA-SHELF')
     when bin_type_name = '34-KIVA-DEEP' then ('KIVA-SHELF')  
     when bin_type_name = '48-KIVA-DEEP' then ('KIVA-SHELF')
     when bin_type_name = '48-KIVA-XL' then ('KIVA-SHELF')
     when bin_type_name = '78-KIVA-TALL' then ('KIVA-SHELF')
     when bin_type_name = 'PALLET-SINGLE' and usage = '1024' then ('KIVA-PALLET')  
     else 'NON-KIVA' end as Location
from icqa_process_locations
join bins on bins.bin_id = icqa_process_locations.scannable_id
inner join icqa_processes on icqa_processes.icqa_process_id = icqa_process_locations.icqa_process_id
inner join icqa_process_properties on icqa_processes.icqa_process_id = icqa_process_properties.icqa_process_id
--inner join icqa_count_attempts on icqa_count_attempts.icqa_count_attempt_id = icqa_process_locations.icqa_count_attempt_id
where icqa_process_locations.icqa_count_attempt_id is NULL 
     and icqa_processes.process_status = ('Active')     
     and icqa_process_properties.icqa_process_property_value in ('CycleCount', 'SimpleBinCount')
group by CASE when bin_type_name = '14-KIVA-DEEP' then ('KIVA-SHELF')  
    when bin_type_name = '18-KIVA-DEEP' then ('KIVA-SHELF')
    when bin_type_name = '24-KIVA-DEEP' then ('KIVA-SHELF')
    when bin_type_name = '30-KIVA-DEEP' then ('KIVA-SHELF')
    when bin_type_name = '34-KIVA-DEEP' then ('KIVA-SHELF')  
    when bin_type_name = '48-KIVA-DEEP' then ('KIVA-SHELF')
    when bin_type_name = '48-KIVA-XL' then ('KIVA-SHELF')
    when bin_type_name = '78-KIVA-TALL' then ('KIVA-SHELF')
    when bin_type_name = 'PALLET-SINGLE' and usage = '1024' then ('KIVA-PALLET')  
    else 'NON-KIVA' end, bin_level, bin_module, icqa_process_properties.icqa_process_property_value
order by icqa_process_properties.icqa_process_property_value, Location))
SELECT Count_Type || Location,
       SUM(CASE when "Mod" = 'dz-P-1A' THEN Remaining_Counts else 0 END ) AS "P-1-A",
       SUM(CASE when "Mod" = 'dz-P-2A' THEN Remaining_Counts else 0 END ) AS "P-2-A",
       SUM(CASE when "Mod" = 'dz-R-1T' THEN Remaining_Counts else 0 END ) AS "R-1-T",
       SUM(CASE when "Mod" = 'dz-R-1F' THEN Remaining_Counts else 0 END ) AS "R-1-F",
       SUM(CASE when "Mod" = 'dz-R-1O' THEN Remaining_Counts else 0 END ) AS "R-1-O",
       SUM(CASE when "Mod" = 'dz-P-1B' THEN Remaining_Counts else 0 END ) AS "P-1-B",
       SUM(CASE when "Mod" = 'dz-P-1D' THEN Remaining_Counts else 0 END ) AS "P-1-D"
FROM   qry
GROUP BY Count_Type || Location;

输出是这个(ALMOST THERE!):

And the output is this(ALMOST THERE!):

但是,当我尝试添加类型时,它会产生零.在添加类型之前,它可以正常工作,但是我可能在某些地方错过了语法.谢谢.

But, it is producing Zero's When I tried to add type. Before I added the types it worked fine, but I may have missed syntax somewhere. Thanks.

推荐答案

您可以执行以下操作:

SQL小提琴

Oracle 11g R2架构设置:

CREATE TABLE tbl ( "mod", "floor", "Remaining Counts", CountType ) AS
          SELECT 'dz-P-1A', 1,    37, 'CycleCount' FROM DUAL
UNION ALL SELECT 'dz-P-1D', 1,   321, 'CycleCount' FROM DUAL
UNION ALL SELECT 'dz-P-1T', 1,    16, 'CycleCount' FROM DUAL
UNION ALL SELECT 'dz-P-2A', 2,    25, 'CycleCount' FROM DUAL
UNION ALL SELECT 'dz-R-1T', 1,  3318, 'CycleCount' FROM DUAL
UNION ALL SELECT 'dz-P-1A', 1,  6351, 'SimpleBinCount' FROM DUAL
UNION ALL SELECT 'dz-P-1D', 1,   121, 'SimpleBinCount' FROM DUAL
UNION ALL SELECT 'dz-P-2A', 2, 12638, 'SimpleBinCount' FROM DUAL
UNION ALL SELECT 'dz-R-1F', 1,    68, 'SimpleBinCount' FROM DUAL
UNION ALL SELECT 'dz-R-1O', 1,    47, 'SimpleBinCount' FROM DUAL
UNION ALL SELECT 'dz-R-1T', 1,  2051, 'SimpleBinCount' FROM DUAL;

查询1 :

使用SUM( CASE ... )语句的PIVOT:

PIVOT using SUM( CASE ... ) statements:

SELECT CountType,
       SUM( CASE "mod" WHEN 'dz-P-1A' THEN "Remaining Counts" END ) AS "P-1-A",
       SUM( CASE "mod" WHEN 'dz-P-2A' THEN "Remaining Counts" END ) AS "P-2-A",
       SUM( CASE "mod" WHEN 'dz-R-1T' THEN "Remaining Counts" END ) AS "R-1-T",
       SUM( CASE "mod" WHEN 'dz-R-1F' THEN "Remaining Counts" END ) AS "R-1-F",
       SUM( CASE "mod" WHEN 'dz-R-1O' THEN "Remaining Counts" END ) AS "R-1-O",
       SUM( CASE "mod" WHEN 'dz-P-1B' THEN "Remaining Counts" END ) AS "P-1-B",
       SUM( CASE "mod" WHEN 'dz-P-1D' THEN "Remaining Counts" END ) AS "P-1-D"
FROM   tbl
GROUP BY CountType

结果 :

Results:

|      COUNTTYPE | P-1-A | P-2-A | R-1-T |  R-1-F |  R-1-O |  P-1-B | P-1-D |
|----------------|-------|-------|-------|--------|--------|--------|-------|
| SimpleBinCount |  6351 | 12638 |  2051 |     68 |     47 | (null) |   121 |
|     CycleCount |    37 |    25 |  3318 | (null) | (null) | (null) |   321 |

查询2 :

使用PIVOT换位:

SELECT * FROM (
   SELECT SUBSTR( "mod", 4 ) AS "mod",
          "Remaining Counts",
          CountType
   FROM   tbl t
)
PIVOT
(
   SUM("Remaining Counts")
   FOR "mod" IN ( 'P-1A', 'P-2A', 'R-1T', 'R-1F', 'R-1O', 'P-1B', 'P-1D' )
)

结果 :

Results:

|      COUNTTYPE | 'P-1A' | 'P-2A' | 'R-1T' | 'R-1F' | 'R-1O' | 'P-1B' | 'P-1D' |
|----------------|--------|--------|--------|--------|--------|--------|--------|
| SimpleBinCount |   6351 |  12638 |   2051 |     68 |     47 | (null) |    121 |
|     CycleCount |     37 |     25 |   3318 | (null) | (null) | (null) |    321 |

编辑-包装查询:

WITH qry AS (
  select drop_zone_id as "Mod", 
      bin_level as "Floor",
      icqa_process_properties.icqa_process_property_value as "Count Type",
      count(*) as "Remaining Counts",    
      concat(drop_zone_id, icqa_process_properties.icqa_process_property_value) as "Unique",
      to_char(sysdate,'hh:mi:ssam') as "Time Last Updated",
      to_char(sysdate, 'MM-DD-YYYY') as "Date Last Updated"
  from icqa_process_locations 
      inner join icqa_processes on icqa_processes.icqa_process_id = icqa_process_locations.icqa_process_id
      inner join icqa_process_properties on icqa_processes.icqa_process_id = icqa_process_properties.icqa_process_id
      inner join bins on bins.bin_id = icqa_process_locations.scannable_id
  where icqa_count_attempt_id is NULL and icqa_processes.process_status = ('Active')
      and drop_zone_id not like 'dz-R-1B' and drop_zone_id not like 'dz-P-1Z' and drop_zone_id not like 'dz-P-EACH_1'
      and icqa_process_properties.icqa_process_property_value in ('CycleCount', 'SimpleBinCount') 
  group by icqa_process_properties.icqa_process_property_value, bin_level, drop_zone_id
  order by icqa_process_properties.icqa_process_property_value, drop_zone_id
)
SELECT "Count Type",
       SUM( CASE "Mod" WHEN 'dz-P-1A' THEN "Remaining Counts" END ) AS "P-1-A",
       SUM( CASE "Mod" WHEN 'dz-P-2A' THEN "Remaining Counts" END ) AS "P-2-A",
       SUM( CASE "Mod" WHEN 'dz-R-1T' THEN "Remaining Counts" END ) AS "R-1-T",
       SUM( CASE "Mod" WHEN 'dz-R-1F' THEN "Remaining Counts" END ) AS "R-1-F",
       SUM( CASE "Mod" WHEN 'dz-R-1O' THEN "Remaining Counts" END ) AS "R-1-O",
       SUM( CASE "Mod" WHEN 'dz-P-1B' THEN "Remaining Counts" END ) AS "P-1-B",
       SUM( CASE "Mod" WHEN 'dz-P-1D' THEN "Remaining Counts" END ) AS "P-1-D"
FROM   qry
GROUP BY "Count Type";

这篇关于Oracle SQL PIVOT表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆