Oracle日期减法 [英] Oracle Date Subtraction

问题描述

我该如何写一个表达式，使我以天，小时，分钟，秒等为单位的两个日期之间的差值?默认情况下，在oracle中减去两个日期将以天为单位返回天.

How would i write an expression that gives me the difference between two dates in days, hours, minutes, seconds, etc? By default subtracting two dates in oracle returns days as a decmial.

推荐答案

该十进制表示所提供的两个日期之间的天数差.您可以做一些数学运算，将其转换为天，小时，分钟，秒等.

That decimal is the number of days difference between the two dates provided. You can do a little math to convert that to days, hours, minutes, seconds, etc.

编辑:我明白了您要查找的内容.我敢肯定有一种更简单的方法，但是我可能会这样完成:

EDIT: I see what you're looking for. I'm sure there's an easier way, but I would probably accomplish it thusly:

select trunc(5.3574585) days, 
       trunc(mod((5.3574585) * 24, 24)) hours, 
       trunc(mod((5.3574585) * 24 * 60, 60)) minutes, 
       trunc(mod((5.3574585) * 24 * 60 * 60, 60)) seconds 
  from dual;

...其中5.3574585是减法返回的天数...

...where 5.3574585 is the number of days returned by the subtraction...

注意:这还没有经过真正的测试，已经超出了我的脑海.

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