将列转置为行oracle [英] transpose column to row oracle

问题描述

我有这种形式的查询返回值(查询返回超过50列).

I have a query returned value in this form (query return more than 50 columns).

 1-99transval  100-200transval  200-300transval ... 1-99nontransval 100...
   50              90                 80                  67           58

获取行值.我希望将这些详细信息转换为列并采用以下形状:

For a row value. I want these details to be converted into columns and take the following shape:

Range       Transval      NonTransval
1-99        50            67
100-200     90            58

推荐答案

在纯 SQL 中，由于需要手动放置范围，因为值和范围之间根本没有关系.如果存在关系，则可以使用 CASE 表达式并动态建立范围.

In pure SQL, it will need a lot of coding because you will have to manually put the range as there is no relation between the values and the range at all. Had there been a relationship, you could use CASE expression and build the range dynamically.

SQL> WITH DATA AS
  2    (SELECT 50 "1-99transval",
  3      90 "100-200transval",
  4      80 "200-300transval",
  5      67 "1-99nontransval",
  6      58 "100-200nontransval",
  7      88 "200-300nontransval"
  8    FROM dual
  9    )
 10  SELECT '1-99' range,
 11    "1-99transval" transval,
 12    "1-99nontransval" nontransval
 13  FROM DATA
 14  UNION
 15  SELECT '100-200' range,
 16    "100-200transval",
 17    "100-200nontransval" nontransval
 18  FROM DATA
 19  UNION
 20  SELECT '200-300' range,
 21    "200-300transval",
 22    "200-300nontransval" nontransval
 23  FROM DATA;

RANGE     TRANSVAL NONTRANSVAL
------- ---------- -----------
1-99            50          67
100-200         90          58
200-300         80          88

在 Oracle数据库11g第1版及更高版本中，您可以使用 UNPIVOT

From Oracle database 11g Release 1 and above, you could use UNPIVOT

SQL> WITH DATA AS
  2    (SELECT 50 "1-99transval",
  3      90 "100-200transval",
  4      80 "200-300transval",
  5      67 "1-99nontransval",
  6      58 "100-200nontransval",
  7      88 "200-300nontransval"
  8    FROM dual
  9    )
 10  SELECT *
 11  FROM   DATA
 12  UNPIVOT( (transval,nontransval)
 13  FOR RANGE IN ( ("1-99transval","1-99nontransval") AS '1-99'
 14                ,("100-200transval","100-200nontransval") AS '100-200'
 15                ,("200-300transval","200-300nontransval") AS '200-300'));

RANGE     TRANSVAL NONTRANSVAL
------- ---------- -----------
1-99            50          67
100-200         90          58
200-300         80          88

在上述情况下，您需要将现有的查询中的 WITH 子句替换为子查询.您需要在 UNION 中添加其他列.

Above, in your case you need to replace the WITH clause with your existing query as a sub-query. You need to include other columns in the UNION.

在 PL/SQL 中，您可以(ab)使用立即执行并通过在<动态SQL .

In PL/SQL, you could (ab)use EXECUTE IMMEDIATE and get the "range" by extracting the column names in dynamic sql.

尽管如此，修改/重写尚未显示的现有查询会更好.

Although, it would be much better to modify/rewrite your existing query which you have not shown yet.

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