替换空格，制表符和回车符 [英] Replace spaces, tabs and carriage returns

问题描述

我正在与Oracle 11g的SQL开发人员一起工作.我有一个查询，看起来与此类似；

I am working with SQL developer with Oracle 11g. I have a query that looks something along the lines of this;

SELECT [column], [column], [column],...... rs.notes
FROM [table], [table], [table]............ return_sku rs
WHERE [conditions] AND [conditions] AND [conditions]

在return_sku列中有制表符，空格和换行符(我相信这是回车符吗?)我需要在运行查询时使所有这些空格，回车符和制表符消失.

In the return_sku column there are tabs, spaces, and newlines (I believe this is a carriage return?) I need to make all of these spaces, carriage returns and tabs disappear when I run my query.

我对SQL还是很陌生，但是发现的最受欢迎的搜索结果是REPLACE函数.我完全不知道如何使用它，因为我已经尝试了许多不同的方法，但是都没有结果.我已经尝试了以下方法；

I am fairly new to SQL, but the most popular search result I found is the REPLACE function. I have absolutely no idea how to use this, as I've tried this in many different ways with no result. I've tried the following;

SELECT [column], [column], [column],...... REPLACE(rs.notes, Char(10), '')
FROM [table], [table], [table]............ return_sku rs
WHERE [conditions] AND [conditions] AND [conditions]

这给出了错误信息:

ORA-00904: "RS"."NOTES": invalid identifier
00904. 00000 -  "%s: invalid identifier"
*Cause:    
*Action:
Error at Line: 3 Column: 531

如何正确使用此功能?

推荐答案

在Oracle中，如果您只想删除一个字符，则可以省略replace调用的第三个参数，并且字符代码的函数是chr()，而不是char ().

In Oracle if you just want to remove a character you can omit the third argument of the replace call and the function for character codes is chr(), not char().

所以您的行将是SELECT ... replace(rs.notes,chr(10)) ...

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