如何将选择结果存储到Oracle过程中的变量中 [英] How to store selection result in to variable in Oracle procedure
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问题描述
我写了一个简单的过程.我尝试将选择结果存储在变量中.我使用"SELECT INTO"查询,但无法执行此操作.
I write a simple procedure. I try to store selection result in variable. I use "SELECT INTO" query but I can not doing this.
示例:
DECLARE
v_employeeRecord employee%ROWTYPE;
BEGIN
SELECT * INTO v_employeeRecord
FROM Employee WHERE Salary > 10;
END;
推荐答案
您有两种选择.您可以将该查询转换为光标:
You have a couple options. You could turn that query into a cursor:
DECLARE
CURSOR v_employeeRecords IS
SELECT * FROM Employee WHERE Salary > 10;
v_employeeRecord employee%ROWTYPE;
BEGIN
FOR v_employeeRecord IN v_employeeRecords LOOP
/* Do something with v_employeeRecord */
END LOOP;
END;
或者,您可以创建一个TABLE
变量:
Or, you can create a TABLE
variable:
DECLARE
v_employeeRecord employee%ROWTYPE;
v_employeeRecords IS TABLE OF employee%ROWTYPE;
i BINARY_INTEGER;
BEGIN
SELECT * BULK COLLECT INTO v_employeeRecords
FROM Employee WHERE Salary > 10;
i := v_employeeRecords.FIRST;
WHILE v_employeeRecords.EXISTS(i) LOOP
v_employeeRecord := v_employeeRecords(i);
/* Do something with v_employeeRecord */
i := v_employeeRecords.NEXT(i);
END;
END;
我没有在Oracle中尝试过这些示例,因此您可能会遇到编译器错误...
I haven't tried these samples in Oracle, so you may get compiler errors...
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