您在范围内没有隐式应用程序:带有Oracle的PlayFramework [英] You do not have an implicit Application in scope: PlayFramework with Oracle

问题描述

尝试使用播放框架访问oracle数据源时出现以下错误:

Getting following error when trying to access oracle DataSource using play framework:

sbt.PlayExceptions$CompilationException: Compilation error[You do not have an implicit Application in scope. If you want to bring
the current running Application into context, just add import play.api.Play.current]

build.properties:

build.properties:

sbt.version=0.12.2
db.default.driver=oracle.jdbc.driver.OracleDriver
db.default.url="jdbc:oracle:thin:@(.....basic))))"
db.default.user="username"
db.default.pass="passowrd"

Controller Application.scala如下:

Controller Application.scala is as follows:

package controllers

import play.api._
import play.api.mvc._
import play.api.db._


object Application extends Controller {

  val d = DB.getDataSource();

  def index = Action { request => Ok("something") } 

}

是什么导致此问题.一切对我来说都是正确的.

What is causing this issue. Everything looks correct to me.

仅供参考.玩！ 2.1.4(使用Java 1.6.0_24和Scala 2.10.0)

-谢谢

推荐答案

错误消息实际上告诉您该怎么做:您在范围内没有隐式的Application.如果要将当前运行的应用程序置于上下文中，只需添加导入play.api.Play.current .

The error message is actually telling you what to do: You do not have an implicit Application in scope. If you want to bring the current running Application into context, just add import play.api.Play.current.

import play.api.Play.current

这是getDataSource方法的样子:

This is what the getDataSource method look like:

  def getDataSource(name: String = "default")(implicit app: Application): DataSource = app.plugin[DBPlugin].map(_.api.getDataSource(name)).getOrElse(error)

如您所见，它在第二个参数列表中包含一个隐式应用程序，并且编译器正在寻找一个可以在导入中找到的隐式声明的应用程序.

As you can see it takes an implicit Application in the second argument list and the compiler is looking for an implicitly declared Application which can be found in the import.

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