SQL ORACLE每10行向sysdate添加1秒 [英] SQL ORACLE add 1 second to sysdate every 10 rows

问题描述

在动态SQL中，我想每10行添加1秒

In dynamic SQL, I'd like to add 1 second every 10 rows

以下查询无效，显示时间间隔无效"

Following query didn't work, got "the interval is invalid"

select 
rownum
,(round(rownum/10,0)+1)
,sysdate + interval '(round(rownum/10,0)+1)' SECOND
from anytable_with_lots_of_rows
where rownum < 100;

有人吗?谢谢！

推荐答案

经典方法是用一天中的秒数除以，例如

Classic way is the division by the number of seconds in a day, e.g.

with rn as (
select rownum-1 id from dual connect by level <= 100),
rn2 as (select 
id, trunc(id/10) tr_id from rn)
select 
id, tr_id,
sysdate + tr_id / (24*3600) my_date
from rn2;

给予

        ID      TR_ID MY_DATE           
---------- ---------- -------------------
         0          0 28-06-2018 19:05:34 
         1          0 28-06-2018 19:05:34 
         2          0 28-06-2018 19:05:34 
         3          0 28-06-2018 19:05:34 
         4          0 28-06-2018 19:05:34 
         5          0 28-06-2018 19:05:34 
         6          0 28-06-2018 19:05:34 
         7          0 28-06-2018 19:05:34 
         8          0 28-06-2018 19:05:34 
         9          0 28-06-2018 19:05:34 
        10          1 28-06-2018 19:05:35 
        11          1 28-06-2018 19:05:35 
        12          1 28-06-2018 19:05:35 
        13          1 28-06-2018 19:05:35 
        14          1 28-06-2018 19:05:35 
        15          1 28-06-2018 19:05:35 
        16          1 28-06-2018 19:05:35 
        17          1 28-06-2018 19:05:35 
        18          1 28-06-2018 19:05:35

或者，如果要使用间隔，请使用函数

Alternatively, if you want to use intervals - use the function NUMTODSINTERVAL

并用以下表达式替换除法

and replace the division with the following expression

sysdate + NUMTODSINTERVAL(tr_id,'SECOND') my_date 

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