在Oracle中减去时间戳，返回奇怪的数据 [英] Subtracting timestamp in oracle returning weird data

问题描述

我正在尝试减去两个日期，并期望返回一些浮动值.但是我得到的回报如下:

I'm trying to subtract two dates and expecting some floating values return. But what I got in return is as below:

+000000000 00:00:07.225000

将值乘以86400(我想以秒为单位)就得到了返回值甚至更奇怪的值:

Multiplying the value by 86400 (I want to get the difference in second) is getting something even more strange value being returned:

+000000007 05:24:00.000000000

有什么主意吗?我怀疑这与类型转换有关.

any idea? I'm suspecting is has something to do with type casting.

推荐答案

我想您的列定义为timestamp而不是date.

I guess your columns are defined as timestamp rather than date.

减去时间戳记的结果是interval，而减去date列的结果是一个数字，代表两个日期之间的天数.

The result of subtracting timestamps is an interval whereas the result of subtracting date columns is a number representing the number of days between the two dates.

这在手册中有记录:
http://docs.oracle.com/cd/E11882_01 /server.112/e41084/sql_elements001.htm#i48042

This is documented in the manual:
http://docs.oracle.com/cd/E11882_01/server.112/e41084/sql_elements001.htm#i48042

因此，当您将时间戳列转换为最新日期时，您应该会得到期望的结果:

So when you cast your timestamp columns to date, you should get what you expect:

with dates as (
   select timestamp '2012-04-27 09:00:00' as col1,
          timestamp '2012-04-26 17:35:00' as col2
   from dual
)
select col1 - col2 as ts_difference,
       cast(col1 as date) - cast(col2 as date) as dt_difference
from dates;

修改:

如果要转换间隔，例如秒(以数字为单位)，您可以执行以下操作:

If you want to convert the interval so e.g. the number of seconds (as a number), you can do something like this:

with dates as (
   select timestamp '2012-04-27 09:00:00.1234' as col1,
          timestamp '2012-04-26 17:35:00.5432' as col2
   from dual
)
select col1 - col2 as ts_difference,
       extract(hour from (col1 - col2)) * 3600 +  
       extract(minute from (col1 - col2)) * 60 + 
       (extract(second from (col1 - col2)) * 1000) / 1000 as seconds
from dates;

以上结果为55499.5802

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