获取总数 [英] Get Total count
本文介绍了获取总数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想合并两列(发送方和接收方)并获取交易类型计数,然后使用Sender_Receiver主ID合并另一张表.
I want to merge two columns(Sender and Receiver) and get the Transaction Type count then merge another table with using Sender_Receiver primary id.
Sender Receiver Type Amount Date
773787639 777611388 1 300 2/1/2019
773631898 776806843 4 450 8/20/2019
773761571 777019819 6 369 2/11/2019
774295511 777084440 34 1000 1/22/2019
774263079 776816905 45 678 6/27/2019
774386894 777202863 12 2678 2/10/2019
773671537 777545555 14 38934 9/29/2019
774288117 777035194 18 21 4/22/2019
774242382 777132939 21 1275 9/30/2019
774144715 777049859 30 6309 7/4/2019
773911674 776938987 10 3528 5/1/2019
773397863 777548054 15 35892 7/6/2019
776816905 772345091 6 1234 7/7/2019
777035194 775623065 4 453454 7/20/2019
第二张表
Mobile_number Age
773787639 34
773787632 23
774288117 65
我试图得到像这样的桌子
I am try to get like this kind of table
Sender/Receiver Type_1 Type_4 Type_12...... Type_45 Age
773787639 3 2 0 0 23
773631898 1 0 1 2 56
773397863 2 2 0 0 65
772345091 1 1 0 3 32
推荐答案
好的,我已经看过您的老问题,您只需要在sub-query
中的inner join
如下:
Ok, I have seen your old question and you just need inner join
in sub-query
as following:
SELECT
SenderReceiver,
COUNT(CASE WHEN Type = 1 THEN 1 END) AS Type_1,
COUNT(CASE WHEN Type = 2 THEN 1 END) AS Type_2,
COUNT(CASE WHEN Type = 3 THEN 1 END) AS Type_3,
...
COUNT(CASE WHEN Type = 45 THEN 1 END) AS Type_45,
Age -- changes here
FROM
( SELECT sr.SenderReceiver, sr.Type, st.Age from -- changes here
(SELECT Sender AS SenderReceiver, Type FROM yourTable
UNION ALL
SELECT Receiver, Type FROM yourTable) sr
join <second_table> st on st.Mobile_number = sr.SenderReceiver -- changes here
) t
GROUP BY
SenderReceiver,
Age; -- changes here
在上一个查询中所做的更改带有注释-- changes here
.
Changes done in your previous query are marked with comments -- changes here
.
请用表的原始名称替换<second_table>
的名称.
Please replace the name of the <second_table>
with the original name of the table.
干杯!
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