oracle从列中获取所有匹配的事件 [英] oracle get all matched occurrences from a column

问题描述

我有一个表，该表有2列:ID& JOB_Description(文字). 我想编写一个oracle SQL来提取中的所有子字符串 与常规模式匹配的描述列.

I have a table, which has 2 columns: ID & JOB_Description(Text). I would like to write an oracle SQL to extract all substrings in the Description column which match a regular pattern.

但是，我已经学会了如何使用下面的SQL从字符串中提取匹配的子字符串，但是我不知道一次在上述表(列:JOB_Description)上一次对所有数据使用下面的SQL.

However, I have learnt how to extract matched substrings from a string with below SQL, but I have no idea to apply below SQL on all data in one go on the aforementioned table(column:JOB_Description).

SQL从字符串中获取所有匹配的出现:

SQL to get all matched occurrences from a string:

 SELECT REGEXP_SUBSTR(JOB_Description, '(ABC|DE)([[:digit:]]){5}', 1, LEVEL) AS substr
   FROM (
         select 'Please help to repair ABC12345, DE22222' as JOB_Description 
          from DUAL)
  CONNECT BY LEVEL <= REGEXP_COUNT(JOB_Description, '(ABC|DE)([[:digit:]]){5}');

推荐答案

您可以尝试此查询.

 with test as(
  select 'ABC12345, DE22222' as JOB_Description from DUAL union
  select 'Please help to repair ABC12345, DE22222' as JOB_Description from DUAL 
)
SELECT REGEXP_SUBSTR(JOB_Description, '(ABC|DE)([[:digit:]]){5}', 1, LEVEL) AS substr
FROM test
CONNECT BY LEVEL <= REGEXP_COUNT(JOB_Description, '(ABC|DE)([[:digit:]]){5}')
  AND PRIOR JOB_Description = JOB_Description
  AND PRIOR DBMS_RANDOM.VALUE IS NOT NULL

结果:

ABC12345
DE22222
ABC12345
DE22222

可以在此处

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