在Oracle 11G中检查字符串中的数字和字符 [英] Check string for numbers and characters in Oracle 11G

问题描述

我正在做某事.我必须检查一个字符串以进行验证.该字符串具有国家代码和大学代码(来自数据库中自己的表)和一堆数字.现在，我需要验证此字符串.我需要检查国家(地区)代码和大学代码上的字符串，以及是否包含数字(是或否).

I am working on something. I got to check a string for validation. This string has a country code and a university code (from their own tables in the database) and a bunch of numbers. Now I need to validate this string. I need to check this string on the country code and university code and if it has numbers yes or no.

此刻我已经尝试了很多东西.我尝试使用很多if语句，regexp_like，instr，substr，select语句和其他语句.但是我无法检查该字符串的国家和大学代码(以及是否具有匹配的数字).

I have tried alot of things at the moment. I tried to use alot of if statements, regexp_like, instr, substr, select statements and others. But I am not capable of checking the string for it's country and university code (and if it has matching numbers).

此刻我的代码如下:

create or replace function checkForCorrectness (
  isin varchar2)
return integer
as
  isCorrect integer := 0;
  checkISIN varchar2(50);
  checkCountryCode country.code%type;
  checkUniversityCode university.code%type;

  e_onbekendeLandCode exception;
  e_onbekendeUniCode exception;
  e_lengteNummer exception;
begin
 --checkISIN := isin;
 /*
 if checkISIN like '%NL%'
 then dbms_output.put_line('Beschikt over een landcode');
  if checkISIN like '%KTU%'
   then dbms_output.put_line('Beschikt over een universiteit code');
    if checkISIN like ''
     then dbms_output.put_line('Beschikt over een nummerreeks');
   end if;
  end if;
 end if;
 */
 --select isin
 --into checkISIN
 --from dual
 --where regexp_like(checkISIN, '^[[:digit:]]+$');
 isin := regexp_like(isin, '[[:digit:]]');
 dbms_output.put_line(checkISIN);

  return isCorrect;

exception
 when e_lengteNummer
 then dbms_output.put_line('Foutmelding: Nummereeks is kleiner dan 9');

 when e_onbekendeLandCode
 then dbms_output.put_line('Foutmelding: Landcode is niet geldig of bestaat niet');

 when e_onbekendeUniCode
 then dbms_output.put_line('Foutmelding: Universiteit code is niet geldig of bestaat niet');

end checkForCorrectness;
/
show errors function checkForCorrectness
/*
begin
 dbms_output.put_line(checkForCorrectness('NL 4633 4809 KTU'));
end;

此刻我很困惑，我什至不知道该怎么办.我希望你们中的一些人能帮助我.

At the moment I am so confused I don't even know what to do anymore. I hope some of you guys could help me out.

长话短说.我得到了这个检查值(还有更多):

To make a long story short. I got this check value (and many more):

ASSERT_EQUALS(checkForCorrectness('NL 4633 4809 KTU'),1);
ASSERT_EQUALS(checkForCorrectness('NL 4954 2537 7808 MSM'),1);

输入是一个字符串，其中包含国家/地区代码(NL)，数字(4633 4809)和大学代码(KTU).如果结果为true或经过验证，则返回1，否则返回0.

The input is a string that contains a country code (NL) a number (4633 4809) and a university code (KTU). if the result is true or it is validated it returns 1 else 0.

我希望我的问题不要太含糊.

I hope my question is not too vague.

如果有人可以向我解释我需要执行/执行的功能和步骤，那将很棒

If someone can explain to me what kind of functions and steps I need to make/take, would be awesome

预先感谢

推荐答案

好，我不清楚您在做什么，但是以下内容可能会有所帮助.从数据创建表

ok I'm not exactly clear on what you are doing however maybe the following might help. creating a table from data

create table mytable as select 'NL 4633 4809 KTU' txt from dual;

您可以使用正则表达式将单词分成几列

you can use regex to split the words up into columns

SELECT  REGEXP_SUBSTR (txt, '[^ ]+', 1, 1)    AS part_1
,       REGEXP_SUBSTR (txt, '[^ ]+', 1, 2)    AS part_2
,       REGEXP_SUBSTR (txt, '[^ ]+', 1, 3)    AS part_3
,       REGEXP_SUBSTR (txt, '[^ ]+', 1, 4)    AS part_4
FROM    mytable;

这将为您提供4列，单词分开显示.

this would give you 4 columns with your words split out.

part1 part2 part3 part4
NL 4633 4809 KTU

或者您可以将regexp与connect by语句一起使用，以将单词变成行.

or you could use regexp with a connect by statement to turn your words into rows.

select REGEXP_SUBSTR (txt, '[^ ]+', 1, level) val from mytable connect by level <= regexp_count(txt,' ') + 1;

这将给您四行

NL
4633
4809
KTU

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