peewee-与Database()初始化分开定义模型 [英] peewee - Define models separately from Database() initialization
问题描述
我需要使用某些ORM引擎(例如 peewee )在我的python应用程序中处理SQLite数据库.但是,大多数此类库都提供类似这样的语法来定义models.py
:
I need to use some ORM engine, like peewee, for handling SQLite database within my python application. However, most of such libraries offer syntax like this to define models.py
:
import peewee
db = peewee.Database('hello.sqlite')
class Person(peewee.Model):
name = peewee.CharField()
class Meta:
database = db
但是,在我的应用程序中,由于数据库文件名是从导入我的models.py
的模块导入后由外部代码提供的,因此我无法使用这种语法.
However, in my application, i cannot use such syntax since database file name is provided by outside code after import, from module, which imports my models.py
.
如何在知道动态数据库文件名的情况下从定义之外初始化模型?理想情况下,models.py
完全不应该包含数据库"提及,就像普通的ORM一样.
How to initialize models from outside of their definition knowing dynamic database file name? Ideally, models.py
should not contain "database" mentions at all, like normal ORM.
推荐答案
也许您正在查看代理功能: 代理-peewee
Maybe you are looking at proxy feature : proxy - peewee
database_proxy = Proxy() # Create a proxy for our db.
class BaseModel(Model):
class Meta:
database = database_proxy # Use proxy for our DB.
class User(BaseModel):
username = CharField()
# Based on configuration, use a different database.
if app.config['DEBUG']:
database = SqliteDatabase('local.db')
elif app.config['TESTING']:
database = SqliteDatabase(':memory:')
else:
database = PostgresqlDatabase('mega_production_db')
# Configure our proxy to use the db we specified in config.
database_proxy.initialize(database)
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