如何在Java中获取当前的类名(包括包名)? [英] How to get current class name including package name in Java?

问题描述

我正在一个项目上，一个要求是，如果main方法的第二个参数以"/"(对于linux)开头，则应将其视为绝对路径(不是问题)，但如果不是以"/"开头，它应该获取该类的当前工作路径，并在其后附加给定的参数.

I'm working on a project and one requirement is if the 2nd argument for the main method starts with "/" (for linux) it should consider it as an absolute path (not a problem), but if it doesn't start with "/", it should get the current working path of the class and append to it the given argument.

我可以通过几种方式获取类名:System.getProperty("java.class.path")，new File(".")和getCanonicalPath()，依此类推...

I can get the class name in several ways: System.getProperty("java.class.path"), new File(".") and getCanonicalPath(), and so on...

问题是，这仅给我提供了存储软件包的目录-即，如果我在".../project/this/is/package/name"中存储了一个类，则只会给我"/project/"，而忽略软件包名称，其中实际的.class files生活.

The problem is, this only gives me the directory in which the packages are stored - i.e. if I have a class stored in ".../project/this/is/package/name", it would only give me "/project/" and ignores the package name where the actual .class files lives.

有什么建议吗?

这是从练习说明中得到的解释

Here's the explanation, taken from the exercise description

sourcedir可以是绝对的(以"/"开头)，也可以是相对于我们运行程序的位置

sourcedir can be either absolute (starting with "/") or relative to where we run the program from

sourcedir是main方法的给定参数.我怎么找到那条路?

sourcedir is a given argument for the main method. how can I find that path?

推荐答案

使用this.getClass().getCanonicalName()获取完整的类名.

请注意，包/类名("abC")与.class文件(a/b/C.class)的路径不同，通常使用包名/类名来派生路径.坏习惯.类文件/程序包的集合可以位于多个不同的类路径中，这些路径可以是目录或jar文件.

Note that a package / class name ("a.b.C") is different from the path of the .class files (a/b/C.class), and that using the package name / class name to derive a path is typically bad practice. Sets of class files / packages can be in multiple different class paths, which can be directories or jar files.

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