创建流时无需创建物理文件 [英] Create a Stream without having a physical file to create from

问题描述

我需要创建一个包含服务器上存在的文档的zip文件.我正在使用.Net Package类来执行此操作，并创建一个新的Package(它是zip文件)，我必须具有物理文件或流的路径.我试图不创建将是zip文件的实际文件，而是仅创建将存在于内存或其他内容中的流.

I'm needing to create a zip file containing documents that exist on the server. I am using the .Net Package class to do so, and to create a new Package (which is the zip file) I have to have either a path to a physical file or a stream. I am trying to not create an actual file that would be the zip file, instead just create a stream that would exist in memory or something.

我的问题是如何在没有物理文件实例化的情况下如何实例化新的Stream(即FileStream，MemoryStream等).

My question is how do you instantiate a new Stream (i.e. FileStream, MemoryStream, etc) without having a physical file to instantiate from.

推荐答案

构造函数重载，都不需要文件.

MemoryStream has several constructor overloads, none of which require a file.

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