Django分页显示问题:显示所有页码 [英] Django Pagination Display Issue: all the page numbers show up

问题描述

有什么方法可以使django分页的页面显示更好?我按照[doc] [1]进行创建，但希望有一种简单的方法来组织页码显示.

is there any way to make page display of django pagination better? I followed the [doc][1] to create it, but hoping there is simple way to organize page number display.

当前，它显示所有页面，例如我有10页，然后
上一页1 2 3 4 5 6 7 8 9 10下一页

Currently, it shows all the pages, say I have 10 pages, then
prev 1 2 3 4 5 6 7 8 9 10 next

如果有100，那么它将显示所有100，这非常疯狂.

If there is 100, then it will show all 100, which is pretty crazy.

有没有一种简单的方法可以将其显示得更短?

Is there any way simple way to display it shorter?

示例:

上一页1 2 3 ... 67 ...下一个98、99、100(当前页面为67)

prev 1 2 3 ... 67 ... 98, 99, 100 next (67 is the current page)

上一页1 2 3 ... 65 66 67 68 69 ... 100下一个

prev 1 2 3 ... 65 66 67 68 69 ... 100 next

它不必看起来像上面的示例，但是只是不想让它显示没有限制的每个页码.

It doesn't have to look like above examples, but just don't want it to show every single page number without limits.

就像文档一样，我使用以下代码创建了分页.

Just like the doc, I created my pagination using below codes.

模板文件

{% if is_paginated %}
<div id="pagination">
<ul>
    {% if page_obj.has_previous %}
        <li> <a href="?page={{page_obj.previous_page_number}}">Previous</a> </li>
    {% else %}
        <li> Previous</li>
    {% endif %}
    {% for page_number in paginator.num_pages|template_range %}
        {% ifequal page_number page_obj.number %}
            <li class="currentpage">{{page_number}}</li>
        {% else %}
            <li> <a href="?page={{page_number}}">{{page_number}}</a> </li>
        {% endifequal %}
    {% endfor %}
    {% if page_obj.has_next %}
        <li> <a href="?page={{page_obj.next_page_number}}">Next</a></li>
    {% else %}
        <li> Next </li>
    {% endif %}
</ul>
</div>
{% endif %}

Views.py

news = News.active.all().order_by("-created_at")
paginator = Paginator(news, 15)

is_paged = False
page = None

try:
    paginator.validate_number(currpage)
except (EmptyPage, InvalidPage):
    #return bad_or_missing(request, ("Invalid page number"))
    currpage = paginator.num_pages



is_paged = paginator.num_pages > 1
page = paginator.page(currpage)

ctx = RequestContext(request, {
    'all_news_list' : page.object_list,
    'is_paginated' : is_paged,
    'page_obj' : page,
    'paginator' : paginator,
    'featured_categories' : featured_categories,
})

response = render_to_response(template_name, context_instance=ctx)
return response

谢谢.

推荐答案

我使用了" Paginator标记"成功实现您正在寻找的分页样式(通常称为"Digg样式"分页).用法在文章" Django中的分页食谱中进行了说明.

I have used the "Paginator Tag" with success to achieve the style of pagination you are looking for (often called "Digg-style" pagination). Usage is explained in the article "A Recipe for Pagination in Django".

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