如何在一个分页中最多显示5个数字? [英] How to show at most 5 numbers in a pagination?

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问题描述

我有一个分页,我想实现并将其限制为5页,

I have a pagination and I want to achieve and limit it to 5 page numbers,

参见下文:

示例:

 PREVIOUS 1 2 3 4 5 NEXT
 PREVIOUS 20 21 22 23 ... 39 NEXT
 PREVIOUS 59 ... 81 82 83 84 NEXT

只需显示五个页码.
我应该更改和修改代码的哪一部分?

Just five page number that they should be display.
Which part of the code should I alter and modify?

我在组合时遇到麻烦了.

I am having trouble with the combination.

 <?php
 /* Setup page vars for display. */
if ($page == 0) $page = 1;                  //if no page var is given, default to 1.
$prev = $page - 1;                          //previous page is page - 1
$next = $page + 1;                          //next page is page + 1
$lastpage = ceil($total_pages/$limit);      //lastpage is = total pages / items per page, rounded up.
$lpm1 = $lastpage - 1;                      //last page minus 1

/* 
    Now we apply our rules and draw the pagination object. 
    We're actually saving the code to a variable in case we want to draw it more than once.
*/
    $pagination = "";
    if($lastpage > 1)
    {   
        $pagination .= "<div class=\"pagination\">";
    //previous buttons
        if ($page > 1) 
            $pagination.= "<a class='buttons' href=\"$targetpage?page=$prev\">previous</a>";
        else
            $pagination.= "<a class='disabled'><buttons disabled>previous</buttons></a>";   

    //pages 
    if ($lastpage < 7 + ($adjacents * 2))   //not enough pages to bother breaking it up
    {   
        for ($counter = 1; $counter <= $lastpage; $counter++)
        {
            if ($counter == $page)
                $pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
            else
                $pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";                 
        }
    }
    elseif($lastpage > 5 + ($adjacents * 2))    //enough pages to hide some
    {
        //close to beginning; only hide later pages
        if($page < 1 + ($adjacents * 2))        
        {
            for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
            {
                if ($counter == $page)
                    $pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
                else
                    $pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";                 
            }
            $pagination.= "...";
            $pagination.= "<a class='buttons' href=\"$targetpage?page=$lpm1\">$lpm1</a>";
            $pagination.= "<a class='buttons' href=\"$targetpage?page=$lastpage\">$lastpage</a>";       
        }
        //in middle; hide some front and some back
        elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
        {
            $pagination.= "<a class='buttons' href=\"$targetpage?page=1\"> 1 </a>";
            $pagination.= "<a class='buttons' href=\"$targetpage?page=2\"> 2 </a>";
            $pagination.= "...";
            for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
            {
                if ($counter == $page)
                    $pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
                else
                    $pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";                 
            }
            $pagination.= "...";
            $pagination.= "<a class='buttons' href=\"$targetpage?page=$lpm1\">$lpm1</a>";
            $pagination.= "<a class='buttons' href=\"$targetpage?page=$lastpage\">$lastpage</a>";       
        }
        //close to end; only hide early pages
        else
        {
            $pagination.= "<a href=\"$targetpage?page=1\">1</a>";
            $pagination.= "<a href=\"$targetpage?page=2\">2</a>";
            $pagination.= "...";
            for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
            {
                if ($counter == $page)
                    $pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
                else
                    $pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";                 
            }
        }
    }

    //next buttons
    if ($page < $counter - 1) 
        $pagination.= "<a class='buttons' href=\"$targetpage?page=$next\">next</a>";
    else
        $pagination.= "<a class='buttons'>next</a>";
    $pagination.= "</div>\n";       
}
?>

我在跟踪显示页码的限制时遇到问题.

I am having problem tracing the limit for displaying page number.

推荐答案

这对我有用. 您必须将当前的页码和总页数传递给该函数.

This worked for me. You have to pass your current page number and total number of pages to the function.

function pageRange(page,pageCount){

var start = page-2,
    end = page+2;

if(end>pageCount){
    start-=(end-pageCount);
    end=pageCount;
}
if(start<=0){
    end+=((start-1)*(-1));
    start=1;
}

end = end>pageCount?pageCount:end;

return {start:start, end:end};
}

查看我制作的这个小提琴 https://jsfiddle.net/qsLp6ajL/2/

check out this fiddle i made https://jsfiddle.net/qsLp6ajL/2/

这篇关于如何在一个分页中最多显示5个数字?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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