为什么groupby sum不将布尔值转换为int或float? [英] Why doesn't groupby sum convert boolean to int or float?
问题描述
我将从3个简单的示例开始:
I'll start with 3 simple examples:
pd.DataFrame([[True]]).sum()
0 1
dtype: int64
pd.DataFrame([True]).sum()
0 1
dtype: int64
pd.Series([True]).sum()
1
所有这些均符合预期.这是一个更复杂的示例.
All of these are as expected. Here is a more complicated example.
df = pd.DataFrame([
['a', 'A', True],
['a', 'B', False],
['a', 'C', True],
['b', 'A', True],
['b', 'B', True],
['b', 'C', False],
], columns=list('XYZ'))
df.Z.sum()
4
也符合预期.但是,如果我groupby(['X', 'Y']).sum()
Also as expected. However, if I groupby(['X', 'Y']).sum()
我希望它看起来像:
我在想错误.还有另一种解释吗?
I'm thinking bug. Is there another explanation?
每个@unutbu的答案
Per @unutbu's answer
pandas尝试将其重铸为原始dtypes.我以为也许我所表演的小组并没有真正地对任何小组进行分组.所以我尝试了这个例子来验证这个想法.
pandas is trying to recast as original dtypes. I had thought that maybe the group by I'd performed didn't really groupby anything. So I tried this example to test out the idea.
df = pd.DataFrame([
['a', 'A', False],
['a', 'B', False],
['a', 'C', True],
['b', 'A', False],
['b', 'B', False],
['b', 'C', False],
], columns=list('XYZ'))
我将groupby('X')
和sum
.如果@unutbu是正确的,则这些总和应为1
和0
并可以转换为bool
,因此我们应该看到bool
I'll groupby('X')
and sum
. If @unutbu is correct, these sums should be 1
and 0
and are castable to bool
, therefore we should see bool
df.groupby('X').sum()
果然... bool
但是,如果过程相同,但值略有不同.
But if the process is the same but the values are slightly different.
df = pd.DataFrame([
['a', 'A', True],
['a', 'B', False],
['a', 'C', True],
['b', 'A', False],
['b', 'B', False],
['b', 'C', False],
], columns=list('XYZ'))
df.groupby('X').sum()
经验教训.执行此操作时,请始终使用astype(int)
或类似的方法.
lesson learned. Always use astype(int)
or something similar when doing this.
df.groupby('X').sum().astype(int)
在任何一种情况下都能获得一致的结果.
gives consistent results for either scenario.
推荐答案
之所以会发生这种情况,是因为 _try_cast_result
,它尝试返回与原始值(在本例中为bool
)相同的dtype 的结果.
This occurs because _cython_agg_blocks
calls _try_coerce_and_cast_result
which calls _try_cast_result
which tries to return a result of the same dtype as the original values (in this case, bool
).
当Z
具有dtype bool(并且所有组的不超过一个True值)时,这将返回一些特殊的信息.如果这些组中的任何一个具有2个或多个True值,则由于_try_cast_result
不会将2.0转换回布尔值,因此结果值将为浮点数.
This returns something a little peculiar when Z
has dtype bool (and all the groups have no more than one True value). If any of the groups have 2 or more True values, then the resulting values are floats since _try_cast_result
does not convert 2.0 back to a boolean.
_try_cast_result
会做些更有用的事情:在内部,供以下人员使用的Cython聚合器
df.groupby(['X', 'Y']).sum()
返回dtype float
的result
.然后,在这里_try_cast_result
将结果返回到dtype int
.
_try_cast_result
does something more useful when Z
has dtype int
: Internally, the Cython aggregator used by
df.groupby(['X', 'Y']).sum()
returns a result
of dtype float
. Here then, _try_cast_result
returns the result to dtype int
.
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