pandas 取消堆叠问题:ValueError:索引包含重复的条目,无法重塑 [英] Pandas unstack problems: ValueError: Index contains duplicate entries, cannot reshape
问题描述
我正尝试与大熊猫解开多重索引,而我不断得到:
I am trying to unstack a multi-index with pandas and I am keep getting:
ValueError: Index contains duplicate entries, cannot reshape
给出具有四列的数据集:
Given a dataset with four columns:
- id(字符串)
- 日期(字符串)
- 位置(字符串)
- 值(浮动)
我首先设置一个三级多索引:
I first set a three-level multi-index:
In [37]: e.set_index(['id', 'date', 'location'], inplace=True)
In [38]: e
Out[38]:
value
id date location
id1 2014-12-12 loc1 16.86
2014-12-11 loc1 17.18
2014-12-10 loc1 17.03
2014-12-09 loc1 17.28
然后我尝试拆开位置:
In [39]: e.unstack('location')
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-39-bc1e237a0ed7> in <module>()
----> 1 e.unstack('location')
...
C:\Anaconda\envs\sandbox\lib\site-packages\pandas\core\reshape.pyc in _make_selectors(self)
143
144 if mask.sum() < len(self.index):
--> 145 raise ValueError('Index contains duplicate entries, '
146 'cannot reshape')
147
ValueError: Index contains duplicate entries, cannot reshape
这是怎么回事?
推荐答案
下面是一个示例DataFrame,它显示了这一点,它具有具有相同索引的重复值.问题是,您是要汇总这些数据还是将其保留为多行?
Here's an example DataFrame which show this, it has duplicate values with the same index. The question is, do you want to aggregate these or keep them as multiple rows?
In [11]: df
Out[11]:
0 1 2 3
0 1 2 a 16.86
1 1 2 a 17.18
2 1 4 a 17.03
3 2 5 b 17.28
In [12]: df.pivot_table(values=3, index=[0, 1], columns=2, aggfunc='mean') # desired?
Out[12]:
2 a b
0 1
1 2 17.02 NaN
4 17.03 NaN
2 5 NaN 17.28
In [13]: df1 = df.set_index([0, 1, 2])
In [14]: df1
Out[14]:
3
0 1 2
1 2 a 16.86
a 17.18
4 a 17.03
2 5 b 17.28
In [15]: df1.unstack(2)
ValueError: Index contains duplicate entries, cannot reshape
一种解决方案是使用reset_index
(然后返回df
)并使用pivot_table
.
One solution is to reset_index
(and get back to df
) and use pivot_table
.
In [16]: df1.reset_index().pivot_table(values=3, index=[0, 1], columns=2, aggfunc='mean')
Out[16]:
2 a b
0 1
1 2 17.02 NaN
4 17.03 NaN
2 5 NaN 17.28
另一种选择(如果您不想汇总)是添加一个虚拟关卡,将其堆叠,然后放下该虚拟关卡...
Another option (if you don't want to aggregate) is to append a dummy level, unstack it, then drop the dummy level...
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