在每个组 pandas 数据框中对列进行排序并选择前n行 [英] Sorting columns and selecting top n rows in each group pandas dataframe

问题描述

我有一个这样的数据框:

I have a dataframe like this:

mainid  pidx    pidy   score
  1      a        b      2
  1      a        c      5
  1      c        a      7
  1      c        b      2
  1      a        e      8
  2      x        y      1
  2      y        z      3
  2      z        y      5
  2      x        w      12
  2      x        v      1
  2      y        x      6   

我想先groupby on column 'pidx'然后sort score in descending order in each group即每个pidx

I want to groupby on column 'pidx' and then sort score in descending order in each group i.e for each pidx

，然后是select head(2)，即每个组的前2名.

and then select head(2) i.e top 2 from each group.

我正在寻找的结果是这样的:

The result I am looking for is like this:

mainid   pidx    pidy    score
  1        a      e        8
  1        a      c        5
  1        c      a        7
  1        c      b        2
  2        x      w        12
  2        x      y        1
  2        y      x        6
  2        y      z        3
  2        z      y        5

我尝试过的是:

df.sort(['pidx','score'],ascending = False).groupby('pidx').head(2) 

，这似乎可行，但是我不知道如果处理庞大的数据集，这是否是正确的方法.我还能使用什么其他最佳方法来获得这种结果?

and this seems to work, but I dont know if it's the right approach if working on a huge dataset. What other best method can I use to get such result?

推荐答案

有2种解决方案:

1. sort_values 和汇总 head :

1.sort_values and aggregate head:

df1 = df.sort_values('score',ascending = False).groupby('pidx').head(2)
print (df1)

    mainid pidx pidy  score
8        2    x    w     12
4        1    a    e      8
2        1    c    a      7
10       2    y    x      6
1        1    a    c      5
7        2    z    y      5
6        2    y    z      3
3        1    c    b      2
5        2    x    y      1

2. set_index 和聚合 nlargest :

2.set_index and aggregate nlargest:

df = df.set_index(['mainid','pidy']).groupby('pidx')['score'].nlargest(2).reset_index() 
print (df)
  pidx  mainid pidy  score
0    a       1    e      8
1    a       1    c      5
2    c       1    a      7
3    c       1    b      2
4    x       2    w     12
5    x       2    y      1
6    y       2    x      6
7    y       2    z      3
8    z       2    y      5

时间:

np.random.seed(123)
N = 1000000

L1 = list('abcdefghijklmnopqrstu')
L2 = list('efghijklmnopqrstuvwxyz')
df = pd.DataFrame({'mainid':np.random.randint(1000, size=N),
                   'pidx': np.random.randint(10000, size=N),
                   'pidy': np.random.choice(L2, N),
                   'score':np.random.randint(1000, size=N)})
#print (df)

def epat(df):
    grouped = df.groupby('pidx')
    new_df = pd.DataFrame([], columns = df.columns)
    for key, values in grouped:
        new_df = pd.concat([new_df, grouped.get_group(key).sort_values('score', ascending=True)[:2]], 0)
    return (new_df)

print (epat(df))

In [133]: %timeit (df.sort_values('score',ascending = False).groupby('pidx').head(2))
1 loop, best of 3: 309 ms per loop

In [134]: %timeit (df.set_index(['mainid','pidy']).groupby('pidx')['score'].nlargest(2).reset_index())
1 loop, best of 3: 7.11 s per loop

In [147]: %timeit (epat(df))
1 loop, best of 3: 22 s per loop

这篇关于在每个组 pandas 数据框中对列进行排序并选择前n行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！