pandas 时间戳不规则地四舍五入30秒 [英] Pandas Timestamp rounds 30 seconds inconsistently
问题描述
我正在尝试将熊猫的DatetimeIndex(或Timestamp)四舍五入到最近的分钟,但是Timestamps为30秒时我遇到了问题-有些向上舍入,有些向下舍入(这似乎是交替的).>
有什么建议可以解决这个问题,以使30s总是四舍五入?
>>> pd.Timestamp(2019,6,1,6,57,30).round('1T')
Timestamp('2019-06-01 06:58:00')
>>> pd.Timestamp(2019,6,1,6,58,30).round('1T')
Timestamp('2019-06-01 06:58:00')
最好的结果看起来不错,有57m个30s取整为58m,但是我希望最下面的结果可以取整到59m-不小于58m.
四舍五入是一致的;接下来的选择是当在两个整数之间的中间时,选择了偶数整数".您需要上半舍入,这将需要您自己实现.
import numpy as np
import pandas as pd
def half_up_minute(x):
m = (x - x.dt.floor('1T')).dt.total_seconds() < 30 # Round True Down, False Up
return x.where(m).dt.floor('1T').fillna(x.dt.ceil('1T'))
# For indices:
def half_up_minute_idx(idx):
m = (idx - idx.floor('1T')).total_seconds() < 30 # Round True Down, False Up
return pd.Index(np.select([m], [idx.floor('1T')], default=idx.ceil('1T')))
# Sample Data
df = pd.DataFrame({'date': pd.date_range('2019-01-01', freq='15S', periods=10)})
df['rounded'] = half_up_minute(df.date)
输出:
date rounded
0 2019-01-01 00:00:00 2019-01-01 00:00:00
1 2019-01-01 00:00:15 2019-01-01 00:00:00
2 2019-01-01 00:00:30 2019-01-01 00:01:00
3 2019-01-01 00:00:45 2019-01-01 00:01:00
4 2019-01-01 00:01:00 2019-01-01 00:01:00
5 2019-01-01 00:01:15 2019-01-01 00:01:00
6 2019-01-01 00:01:30 2019-01-01 00:02:00
7 2019-01-01 00:01:45 2019-01-01 00:02:00
8 2019-01-01 00:02:00 2019-01-01 00:02:00
9 2019-01-01 00:02:15 2019-01-01 00:02:00
I'm trying to round a pandas DatetimeIndex (or Timestamp) to the nearest minute, but I'm having a problem with Timestamps of 30 seconds - some rounding up, some rounding down (this seems to alternate).
Any suggestions to fix this so that 30s always rounds up?
>>> pd.Timestamp(2019,6,1,6,57,30).round('1T')
Timestamp('2019-06-01 06:58:00')
>>> pd.Timestamp(2019,6,1,6,58,30).round('1T')
Timestamp('2019-06-01 06:58:00')
The top result looks fine, with 57m 30s rounding up to 58m, but I'd expect the bottom result to round up to 59m - not down to 58m.
The rounding is consistent; the choice followed is, "when halfway between two integers the even integer is chosen." You want half-up rounding, which you will need to implement yourself.
import numpy as np
import pandas as pd
def half_up_minute(x):
m = (x - x.dt.floor('1T')).dt.total_seconds() < 30 # Round True Down, False Up
return x.where(m).dt.floor('1T').fillna(x.dt.ceil('1T'))
# For indices:
def half_up_minute_idx(idx):
m = (idx - idx.floor('1T')).total_seconds() < 30 # Round True Down, False Up
return pd.Index(np.select([m], [idx.floor('1T')], default=idx.ceil('1T')))
# Sample Data
df = pd.DataFrame({'date': pd.date_range('2019-01-01', freq='15S', periods=10)})
df['rounded'] = half_up_minute(df.date)
Output:
date rounded
0 2019-01-01 00:00:00 2019-01-01 00:00:00
1 2019-01-01 00:00:15 2019-01-01 00:00:00
2 2019-01-01 00:00:30 2019-01-01 00:01:00
3 2019-01-01 00:00:45 2019-01-01 00:01:00
4 2019-01-01 00:01:00 2019-01-01 00:01:00
5 2019-01-01 00:01:15 2019-01-01 00:01:00
6 2019-01-01 00:01:30 2019-01-01 00:02:00
7 2019-01-01 00:01:45 2019-01-01 00:02:00
8 2019-01-01 00:02:00 2019-01-01 00:02:00
9 2019-01-01 00:02:15 2019-01-01 00:02:00
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