Python 3-Zip是pandas数据框中的迭代器 [英] Python 3 - Zip is an iterator in a pandas dataframe

问题描述

我正在关注熊猫教程

这些教程是使用python 2.7编写的，而我正在python 3.4中进行编写

The tutorials are written using python 2.7 and I am doing them in python 3.4

这是我的版本详细信息.

Here is my version details.

In [11]: print('Python version ' + sys.version)
Python version 3.4.1 |Anaconda 2.0.1 (64-bit)| (default, Jun 11 2014, 17:27:11)
[MSC v.1600 64 bit (AMD64)]

In [12]: print('Pandas version ' + pd.__version__)
Pandas version 0.14.1

我按照教程创建了zip

I create the zip as per the tutorial

In [13]: names = ['Bob','Jessica','Mary','John','Mel']

In [14]: births = [968, 155, 77, 578, 973]

In [15]: zip?
Type:            type
String form:     <class 'zip'>
Namespace:       Python builtin
Init definition: zip(self, *args, **kwargs)
Docstring:
zip(iter1 [,iter2 [...]]) --> zip object

Return a zip object whose .__next__() method returns a tuple where
the i-th element comes from the i-th iterable argument.  The .__next__()
method continues until the shortest iterable in the argument sequence
is exhausted and then it raises StopIteration.

In [16]: BabyDataSet = zip(names,births)

但是创建后，第一个错误表明我看不到zip的内容.

But after creation the first error shows that I cannot see the contents of the zip.

In [17]: BabyDataSet
Out[17]: <zip at 0x4f28848>

In [18]: print(BabyDataSet)
<zip object at 0x0000000004F28848>

然后，当我创建数据框时，出现此迭代器错误.

Then when I go to create the dataframe I get this iterator error.

In [21]: df = pd.DataFrame(data = BabyDataSet, columns=['Names', 'Births'])
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-21-636a49c94b6e> in <module>()
----> 1 df = pd.DataFrame(data = BabyDataSet, columns=['Names', 'Births'])

c:\Users\Sayth\Anaconda3\lib\site-packages\pandas\core\frame.py in __init__(self
, data, index, columns, dtype, copy)
    255                                          copy=copy)
    256         elif isinstance(data, collections.Iterator):
--> 257             raise TypeError("data argument can't be an iterator")
    258         else:
    259             try:

TypeError: data argument can't be an iterator

In [22]:

这是我需要以其他方式执行的python 3陷阱吗?还是其他?

Is this a python 3 gotcha where I need to do it differently? Or other?

推荐答案

您需要更改以下行:

BabyDataSet = zip(names,births)

收件人:

BabyDataSet = list(zip(names,births))

这是因为zip现在在python 3中返回一个迭代器，因此出现了错误消息.有关更多详细信息，请参见: http://www.diveintopython3.net/porting -code-to-python-3-with-2to3.html#zip 和 https://docs.python.org/3/library/functions.html#zip

This is because zip now returns an iterator in python 3, hence your error message. For more details see: http://www.diveintopython3.net/porting-code-to-python-3-with-2to3.html#zip and https://docs.python.org/3/library/functions.html#zip

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