在Pandas中使散点图的标签垂直和水平 [英] Making the labels of the scatterplot vertical and horizontal in Pandas
问题描述
我正在使用Pandas
绘制散点图矩阵:from pandas.tools.plotting import scatter_matrix
.问题是DataFrame
中的列名太长,我需要它们在x轴上是垂直的,在y轴上是水平的,以便它们适合.我根本无法弄清楚如何在Pandas中做到这一点.我知道如何在matplotlib
中做到这一点,但在Pandas中却不知道.
I'm using Pandas
to draw a scatterplot matrix: from pandas.tools.plotting import scatter_matrix
. The problem is that the names of the columns in the DataFrame
are too long and I need them to be vertical in the x-axis and horizontal in the y-axis so they can fit. I'm not able to figure out at all how to do that in Pandas. I know how to do it in matplotlib
but not in Pandas.
我的代码:
pylab.clf()
df = pd.DataFrame(X, columns=the_labels)
axs = scatter_matrix(df, alpha=0.2, diagonal='kde')
我需要使用pylab.clf()
,因为我要绘制很多图形,因此每次调用pylab.figure()
都会占用大量内存.
I need to use pylab.clf()
because I'm plotting a lot of figures, so calling pylab.figure()
each time is too memory consuming.
推荐答案
此答案的主要帮助: https://stackoverflow.com /a/18994338/2632856
a = [[1,2], [2,3], [3,4], [4, 5], [1, 6], [2,7], [1,8]]
df = pd.DataFrame(a,columns=['askdabndksbdkl','aooweoiowiaaiwi'])
axs = pd.scatter_matrix( df, alpha=0.2, diagonal='kde')
n = len(df.columns)
for x in range(n):
for y in range(n):
# to get the axis of subplots
ax = axs[x, y]
# to make x axis name vertical
ax.xaxis.label.set_rotation(90)
# to make y axis name horizontal
ax.yaxis.label.set_rotation(0)
# to make sure y axis names are outside the plot area
ax.yaxis.labelpad = 50
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