pandas :SettingWithCopyWarning触发器位置 [英] Pandas: SettingWithCopyWarning trigger location
问题描述
对于SettingWithCopyWarning
,有时它会将您引向触发警告的模块中的确切代码行(例如在此).
With SettingWithCopyWarning
, sometimes it refers you to the exact line of code in your module that triggered the warning (e.g. here) and other times it doesn't (e.g. here).
简短地遍历代码的每一行(如果您正在查看数百行代码,听起来不太吸引人),如果没有警告,有一种方法可以查明触发警告的代码行返回该信息?
Short of going through each line of the code (doesn't sound too appealing if you're reviewing hundreds of lines of code), is there a way to pinpoint the line of code that triggered the warning assuming the warning does not return that information?
我想知道这是否是警告中的错误,以便在不查明触发该警告的特定代码的情况下返回警告.
I wonder if this is a bug in the warning to return a warning without pinpointing the specific code that triggered it.
Warning (from warnings module):
File "C:\Python34\lib\site-packages\pandas\core\indexing.py", line 415
self.obj[item] = s
SettingWithCopyWarning:
A value is trying to be set on a copy of a slice from a DataFrame.
Try using .loc[row_indexer,col_indexer] = value instead
See the the caveats in the documentation: http://pandas.pydata.org/pandas-docs/stable/indexing.html#indexing-view-versus-copy
Python 3.4,Pandas 0.15.0
推荐答案
通过将mode.chained_assignment
选项设置为raise
而不是warn
,可以使熊猫举起SettingWithCopyError
而不是SettingWithCopyWarning
.
You can have pandas raise SettingWithCopyError
instead of SettingWithCopyWarning
by setting the mode.chained_assignment
option to raise
instead of warn
.
import pandas as pd
pd.set_option('mode.chained_assignment', 'raise')
https://pandas.pydata.org/pandas -docs/stable/options.html#available-options
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