regex不区分大小写对pandas中的列进行过滤 [英] regex case insensitive filtering of columns in pandas

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问题描述

我正在尝试使用Python在python的csv文件中匹配一个字符串(列),但没有任何匹配.我希望匹配的字符串不区分大小写.我很新,但这就是我想要做的

I am trying to match a string(column) in csv files in python using Python but it does not match anything. I want the string to be match to be case insensitive. I am quite new but this is what I tried to do

test = pd.read_csv("data.csv")
mytest= pd.DataFrame(test, columns=[re.search("[a-zA-Z1-9_]", "columnname1", re.IGNORECASE),])
print(mytest)

我们将不胜感激任何帮助

Any help will be highly appreciated

推荐答案

如果我了解您的要求,则可以filter将df仅返回名称匹配的列并使其不区分大小写:

If I understand what you're after you can filter your df to only return the columns where the name matches and make it case-insensitive:

In [298]:

df = pd.DataFrame({'columnname1':np.arange(5), 'ColumnName1':np.arange(5), 'columnname2':0, 'column name 1':0})
df
Out[298]:
   ColumnName1  column name 1  columnname1  columnname2
0            0              0            0            0
1            1              0            1            0
2            2              0            2            0
3            3              0            3            0
4            4              0            4            0

In [299]:

import re
df.filter(regex=re.compile("columnname1", re.IGNORECASE))
Out[299]:
   ColumnName1  columnname1
0            0            0
1            1            1
2            2            2
3            3            3
4            4            4

编辑

仅匹配名称但不带单词,因此匹配测试"而不匹配我的测试":

For matching just the name without words preceding it, so matching on 'Test' but not 'My Test':

In [52]:

df = pd.DataFrame({'Test':np.arange(5), 'ColumnName1':np.arange(5), 'My Test':0, 'My column name 1':0})
import re
df.filter(regex=re.compile(r"^Test$", re.IGNORECASE))
Out[52]:
   Test
0     0
1     1
2     2
3     3
4     4

因此^在str的开头查找'Test',而$标志着要搜索的模式的结尾,这里有一个方便的

So the ^ looks for 'Test' at the beginning of the str and the $ marks the end of the pattern to search, there is a handy cheat sheet.

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