在Pandas数据框中爆炸一行到多行 [英] Explode a row to multiple rows in pandas dataframe
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问题描述
我有一个带有以下标头的数据框:
I have a dataframe with the following header:
id, type1, ..., type10, location1, ..., location10
,我想将其转换如下:
id, type, location
我设法使用嵌入式for循环来做到这一点,但是它非常慢:
I managed to do this using embedded for loops but it's very slow:
new_format_columns = ['ID', 'type', 'location']
new_format_dataframe = pd.DataFrame(columns=new_format_columns)
print(data.head())
new_index = 0
for index, row in data.iterrows():
ID = row["ID"]
for i in range(1,11):
if row["type"+str(i)] == np.nan:
continue
else:
new_row = pd.Series([ID, row["type"+str(i)], row["location"+str(i)]])
new_format_dataframe.loc[new_index] = new_row.values
new_index += 1
是否有使用本地熊猫功能进行改进的建议?
Any suggestions for improvement using native pandas features?
推荐答案
您可以使用lreshape
:
types = [col for col in df.columns if col.startswith('type')]
location = [col for col in df.columns if col.startswith('location')]
print(pd.lreshape(df, {'Type':types, 'Location':location}, dropna=False))
示例:
import pandas as pd
df = pd.DataFrame({
'type1': {0: 1, 1: 4},
'id': {0: 'a', 1: 'a'},
'type10': {0: 1, 1: 8},
'location1': {0: 2, 1: 9},
'location10': {0: 5, 1: 7}})
print (df)
id location1 location10 type1 type10
0 a 2 5 1 1
1 a 9 7 4 8
types = [col for col in df.columns if col.startswith('type')]
location = [col for col in df.columns if col.startswith('location')]
print(pd.lreshape(df, {'Type':types, 'Location':location}, dropna=False))
id Location Type
0 a 2 1
1 a 9 4
2 a 5 1
3 a 7 8
另一种解决方案,具有双重 melt
:
Another solution with double melt
:
print (pd.concat([pd.melt(df, id_vars='id', value_vars=types, value_name='type'),
pd.melt(df, value_vars=location, value_name='Location')], axis=1)
.drop('variable', axis=1))
id type Location
0 a 1 2
1 a 4 9
2 a 1 5
3 a 8 7
lreshape
现在没有文档,但是将来有可能会被删除(与pd一起使用.也是).
可能的解决方案是将所有3个功能合并为一个,也许是melt
,但现在尚未实现.也许是在一些新版本的熊猫中.然后我的答案将被更新.
Possible solution is merging all 3 functions to one - maybe melt
, but now it is not implementated. Maybe in some new version of pandas. Then my answer will be updated.
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