选择两个DatetimeIndex日期之间的行 [英] Select rows between two DatetimeIndex dates

问题描述

我有以下格式的CSV文件:

I have a CSV file of the following format:

vm,time,LoadInt1
abc-webapp-02,2017-05-31 10:00:00,3.133333
abc-webapp-02,2017-05-31 10:05:00,0.000000
abc-webapp-02,2017-05-31 10:10:00,0.000000
abc-webapp-02,2017-05-31 10:15:00,0.000000
abc-webapp-02,2017-05-31 10:20:00,0.000000
abc-webapp-02,2017-05-31 10:25:00,0.000000
abc-webapp-02,2017-05-31 10:30:00,0.000000
abc-webapp-02,2017-05-31 10:35:00,0.000000
abc-webapp-02,2017-05-31 10:40:00,0.000000

我使用以下代码将CSV文件读取到DataFrame中.日期被解析为索引(DatetimeIndex)

I read the CSV file into a DataFrame using the following code. The date is parsed as index (DatetimeIndex)

dateparse = lambda x: pd.datetime.strptime(x, '%Y-%m-%d %H:%M:%S')
df = pd.read_csv("my_file.csv", header=0, parse_dates=[1], index_col=1, date_parser=dateparse)

现在，我正在尝试使用以下代码获取两个日期之间的所有行(真正的CSV文件在下面提到的日期之间具有大量的行):

Now I am trying to get all the rows between two dates using the following code (The real CSV file has large number of rows between the dates mentioned below):

df.loc['2017-05-30' : '2017-05-31']

请注意，建议在此处使用上述方法.但是，它对我不起作用.因此，这可能不是一个重复的问题.

Please note, above approach is suggested here. But, it's not working for me. So, it may not be a duplicate question.

推荐答案

使用query方法:

df = pd.read_csv("my_file.csv", index_col=1, parse_dates=True)

In [121]: df.query("'2017-05-30' <= index <= '2017-06-01'")
Out[121]:
                                vm  LoadInt1
time
2017-05-31 10:00:00  abc-webapp-02  3.133333
2017-05-31 10:05:00  abc-webapp-02  0.000000
2017-05-31 10:10:00  abc-webapp-02  0.000000
2017-05-31 10:15:00  abc-webapp-02  0.000000
2017-05-31 10:20:00  abc-webapp-02  0.000000
2017-05-31 10:25:00  abc-webapp-02  0.000000
2017-05-31 10:30:00  abc-webapp-02  0.000000
2017-05-31 10:35:00  abc-webapp-02  0.000000
2017-05-31 10:40:00  abc-webapp-02  0.000000

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