将整个列设置为值Pandas的Pythonic方法(SettingWithCopyWarning) [英] Pythonic way to set entire column to value Pandas (SettingWithCopyWarning)
问题描述
我想将整个列设置为单个字符串值.这样做时,我得到了(曾经如此受欢迎的)SettingWithCopy
.在发布有关此特定问题的信息之前,我尝试过搜索SO.
I want to set an entire column to a single string value. When doing so I get the (ever so popular) SettingWithCopy
. I've tried to search SO before posting about this specific issue.
import pandas as pd
import numpy as np
dfp = pd.DataFrame({'A' : [1,21,8,44,np.NaN,6,75,8,44,999],
'B' : [1,1,3,5,0,0,np.NaN,9,np.NaN,0],
'C' : ['AA1233445','AA1233445', 'rmacy','Idaho Rx','Ab123455','TV192837','RX','Ohio Drugs','RX12345','USA Pharma'],
'D' : [123456,123456,1234567,12345678,12345,12345,12345678,123456789,1234567,np.NaN],
'E' : ['Assign','Assign','Hello','Ugly','Appreciate','Undo','Testing','Unicycle','Pharma','Unicorn',]})
print(dfp)
new_df_to_show_copy = dfp.loc[(dfp['A']>100) |(dfp['E']=='Unicorn')]
new_df_to_show_copy['Reason'] = 'what is with the copy warning'
现在我可以用
new_df_to_show_copy = dfp.loc[(dfp['A']>100) |(dfp['E']=='Unicorn')].copy() <--Notice copy()
new_df_to_show_copy['Reason'] = 'what is with the copy warning'
我知道我可以用pd.options.mode.chained_assignment = None
摆脱警告,但是我觉得那是作弊".我正在看文档,但是找不到在不添加.copy()
或不显示警告的情况下将整个列设置为单个值的最小方法.最好的方法是什么?
And I know I can get rid of the warning with pd.options.mode.chained_assignment = None
but I feel like that's "cheating". I'm looking at the documentation, but can't find a minimal way for setting an entire column to a single value without adding .copy()
or suppressing the warning. What's the best way to do that?
推荐答案
I was working on a similar requirement earlier today and I came across assign
. I got rid of the copy warning without using pd.options.mode.chained_assignment = None
. Here was my solution:
new_df_to_show_copy = dfp.loc[(dfp['A']>100) |(dfp['E']=='Unicorn')]
new_df_to_show_copy = new_df_to_show_copy.assign(Reason = 'what is with the copy warning')
# output:
A B C D E Reason
9 999.0 0.0 USA Pharma NaN Unicorn what is with the copy warning
assign
将保留数据帧的副本,并且没有inplace=True
参数.因此,只需重新分配对我有用的价值即可.
assign
will leave a copy of the dataframe, and there is no inplace=True
parameter. so just reassigning the value worked for me.
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