从具有重复列的DF中基于列表选择行 [英] Selecting rows - based on a list - from a DF with duplicated columns
本文介绍了从具有重复列的DF中基于列表选择行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下数据框:
import pandas as pd
rep = pd.DataFrame.from_items([('Probe', ['x', 'y', 'z']), ('Gene', ['foo', 'bar', 'qux']), ('Probe',['x','y','z']), ("RP",[1.00,2.33,4.5])], orient='columns')
哪个会产生:
In [11]: rep
Out[11]:
Probe Gene Probe RP
0 x foo x 1.00
1 y bar y 2.33
2 z qux z 4.50
请注意,那里有重复的列. 我要做的是基于列表选择行:
Note that there are duplicate column there. What I want to do is to select the row based on a list:
ls = ["x", "z", "i"]
提供此:
Probe Gene Probe RP
0 x foo x 1.00
2 z qux z 4.50
请注意,我们希望基于上面的原始DF保留列.
Note that we'd like to preserve the columns based on the original DF above.
为什么失败了?
In [9]: rep[rep[[0]].isin(ls)]
ValueError: cannot reindex from a duplicate axis
什么是正确的方法? isin
的替代品吗?
What's the right way to do it? Any alternative to isin
?
推荐答案
您应在此处使用iloc:
You should use iloc here:
In [11]: rep.iloc[rep.iloc[0].isin(ls).values]
Out[11]:
Probe Gene Probe RP
0 x foo x 1.0
2 z qux z 4.5
这首先创建布尔矢量(作为一维数组而不是DataFrame),您可以将其用作掩码:
This first creates the boolean vector (as a one-dimensional array rather than a DataFrame), and you can use this as a mask:
In [12]: rep.iloc[0].isin(ls).values
Out[12]: array([ True, False, True, False], dtype=bool)
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