如何选择所有以"durations"开头的列或“形状"? [英] How to select all columns that start with "durations" or "shape"?

问题描述

如何选择标题名称以"durations"或"shape"开头的所有列? (而不是定义一长列名称).我需要选择这些列并将空白字段替换为0.

How to select all columns that have header names starting with "durations" or "shape"? (instead of defining a long list of column names). I need to select these columns and substitute blank fields by 0.

column_names = ['durations.blockMinutes_x',
                'durations.scheduledBlockMinutes_y']
data[column_names] = data[column_names].fillna(0)

推荐答案

您可以使用数据框startwith的str方法:

You could use str methods of dataframe startwith:

df = data[data.columns[data.columns.str.startwith('durations') | data.columns.str.startwith('so')]]
df.fillna(0)

或者您可以使用contains方法:

df = data.iloc[:, data.columns.str.contains('durations.*'|'shape.*') ]
df.fillna(0)

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