排序父节点XML取决于子节点值 [英] Sort parent nodes XML depends on child nodes values

问题描述

我有以下XML

<Root> 
  <Element A/>
  <Element B/>
  <Data1> 
    <DataElement/> 
    <Values>
       <Value>2222</Value> 
       <Name>field1</Name>
    </Values> 
    <Values>
       <Value>ABC</Value> 
       <Name>field2</Name>
    </Values> 
  </Data1> 
  <Data2> 
    <DataElement/> 
    <Values>
       <Value>1111</Value> 
       <Name>field1</Name>
    </Values> 
    <Values>
       <Value>XYZ</Value> 
       <Name>field2</Name>
    </Values> 
  </Data2>
  <DataN> 
    ... 
  </DataN> 
</Root> 

例如，我需要获取具有Data部分的XML，该XML部分按指定字段名称的值"排序: 按"field1"排序将返回

I need to get the same XML with Data section sorted by "Value" of specified field name, for exmple: sort by "field1" will return

    <Root> 
  <Element A/>
  <Element B/>
  <Data2> 
    <DataElement/> 
    <Values>
       <Value>1111</Value> 
       <Name>field1</Name>
    </Values> 
    <Values>
       <Value>XYZ</Value> 
       <Name>field2</Name>
    </Values> 
  </Data2>
  <Data1> 
    <DataElement/> 
    <Values>
       <Value>2222</Value> 
       <Name>field1</Name>
    </Values> 
    <Values>
       <Value>ABC</Value> 
       <Name>field2</Name>
    </Values> 
  </Data1>   
  <DataN> 
    ... 
  </DataN> 
</Root> 

此外，我必须发送排序字段的名称作为参数...

Also, I have to send name of sort field as parameter...

推荐答案

此转换完全实现了规定的要求.要特别注意保留不排序元素的确切顺序.目前没有其他答案:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:param name="vField" select="'field1'"/>
 <xsl:param name="pSortType" select="'number'"/>

 <xsl:template match="node()|@*" name="identity">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
 </xsl:template>

   <xsl:template match="*[starts-with(name(),'Data')]">
    <xsl:variable name="vPos" select=
      "count(preceding-sibling::*[starts-with(name(),'Data')])+1"/>

  <xsl:for-each select="/*/*[starts-with(name(),'Data')]">
   <xsl:sort select="Values[Name=$vField]/Value"
             data-type="{$pSortType}"/>
   <xsl:if test="position() = $vPos">
    <xsl:copy-of select="."/>
   </xsl:if>
  </xsl:for-each>
 </xsl:template>
</xsl:stylesheet>

应用于以下XML文档(与提供的XML文档相同)，但在Data1和Data2之间插入了附加的<Element C=""/>，以便我们可以验证顺序的保留未排序的元素):

When applied on the following XML document (the same as the provided one, but with an additional <Element C=""/> inserted between Data1 and Data2 so that we can verify the preservation of ordering of the non-sorted elements):

<Root>
    <Element A=""/>
    <Element B=""/>
    <Data1>
        <DataElement/>
        <Values>
            <Value>2222</Value>
            <Name>field1</Name>
        </Values>
        <Values>
            <Value>ABC</Value>
            <Name>field2</Name>
        </Values>
    </Data1>
        <Element C=""/>
    <Data2>
        <DataElement/>
        <Values>
            <Value>1111</Value>
            <Name>field1</Name>
        </Values>
        <Values>
            <Value>XYZ</Value>
            <Name>field2</Name>
        </Values>
    </Data2>
</Root>

产生所需的正确结果-请注意，<Element C=""/>的位置已保留:

produces the wanted, correct result -- note that the position of <Element C=""/> is preserved:

<Root>
   <Element A=""/>
   <Element B=""/>
   <Data2>
      <DataElement/>
      <Values>
         <Value>1111</Value>
         <Name>field1</Name>
      </Values>
      <Values>
         <Value>XYZ</Value>
         <Name>field2</Name>
      </Values>
   </Data2>
   <Element C=""/>
   <Data1>
      <DataElement/>
      <Values>
         <Value>2222</Value>
         <Name>field1</Name>
      </Values>
      <Values>
         <Value>ABC</Value>
         <Name>field2</Name>
      </Values>
   </Data1>
</Root>

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