批量解析每个参数 [英] Batch parse each parameter

问题描述

我正在尝试创建一个批处理脚本，该脚本将对给定的每个参数执行相同的操作.例如，将X文件作为参数:
script.bat "file1.txt" "file2.txt" "file3.txt" "file4.txt" ... "fileX.txt"
将其重命名为:
"file1.bin" "file2.bin" "file3.bin" "file4.bin" ... "fileX.bin"
重命名只是一个例子，对于更复杂的操作，我也将需要它.
我想应该是for each之类的东西，但是我是批处理脚本的新手.

I am trying to create a batch script which would perform the same action for each parameter given. For example, giving X files as parameters:
script.bat "file1.txt" "file2.txt" "file3.txt" "file4.txt" ... "fileX.txt"
will rename them to:
"file1.bin" "file2.bin" "file3.bin" "file4.bin" ... "fileX.bin"
Rename is just an example, I will need it for more complex operations too.
I guess it should be something like for each but I'm new in batch scripts.

我只是想知道我是否可以增加%1索引...

I just wonder if I could just increment %1 index...

推荐答案

您可以使用SHIFT将参数向左移动.换句话说，调用shift将把第二个参数放到％1，第三个参数放到％2，依此类推.

You can use SHIFT to shift the parameters left. In other words calling shift will put the second parameter to %1, the third to %2 etc.

所以您需要类似的东西:

So you need something like:

@ECHO OFF
:Loop
IF "%1"=="" GOTO Continue
   ECHO %1
SHIFT
GOTO Loop
:Continue

这只会按顺序打印参数，但是您可以在循环内做任何您想做的事情.

This will just print the arguments in order, but you can do whatever you want inside the loop.

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