mysql_close()期望参数1为资源，给定null [英] mysql_close() expects parameter 1 to be resource, null given

问题描述

导致错误的行就是这个...

The line causing the error is this one...

mysql_close($con);

这是全部代码...

$con=mysqli_connect("localhost","root","pass","db_name");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM medicos");


    while($row = mysqli_fetch_array($result)) {
    echo '.....';
    }



    mysql_close($con);

推荐答案

必须将行mysql_close($con);更改为mysqli_close($con);

您不能互换使用mysql和mysqli函数，例如:

You cannot interchangeably use mysql and mysqli functions, for example:

mysqli_connect需要使用mysqli_close

-同样-

mysql_connect需要使用mysql_close

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