Python + pyQT-将参数发送到连接的Signal函数 [英] Python + pyQT - send parameters to the connected Signal function

问题描述

此示例有效:(这里我的函数没有输入参数)

This example works: (Here my function has no input parameters)

    QtCore.QObject.connect(ComboJobType1_1, QtCore.SIGNAL(_fromUtf8("currentIndexChanged(QString)")) ,self.InputChanged())

但是，我有必要发送一个参数，所以我尝试这样做:(在更新函数以得到一个参数之后):

But, It is necessary for me to send a parameter so I try this: (After updating my function to expect one parameter):

QtCore.QObject.connect(ComboJobType1_1，QtCore.SIGNAL(_fromUtf8("currentIndexChanged(QString)"))，self.InputChanged("ComboJobType1_1"))

QtCore.QObject.connect(ComboJobType1_1, QtCore.SIGNAL(_fromUtf8("currentIndexChanged(QString)")) ,self.InputChanged("ComboJobType1_1"))

请注意，第一个示例正在工作，唯一的问题(我想)是向函数发送参数(当我进入函数时，我必须知道comboBox的名称).

Please note that the first example is working, the only problem (I guess) is sending a parameter to my function (I must know the name of the comboBox when I'm in the function).

请咨询... 谢谢！ 祝你有美好的一天， 海豚

Please advice... Thank you! Wish you a great day, Dolphin

推荐答案

ref 为我工作，给它一个简单的lambda(将其转换为funciton ref而不是execute吗?

worked for me, tht gives it a simple lambda (turn it to funciton ref instead of execute ?

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