如何从Parse.com获取单个键的所有值 [英] How to fetch all values for a single key from Parse.com

问题描述

我正试图从Parse的PeopleName类中获取所有名称.它没有显示任何构建错误，但出现运行时错误Error: field Name cannot be included because it is not a pointer to another object (Code: 102, Version: 1.2.17).

I'm trying to fetch all the names from my PeopleName class from Parse. It's not showing any build error, but I get a runtime error Error: field Name cannot be included because it is not a pointer to another object (Code: 102, Version: 1.2.17).

这是代码.有帮助吗?

PFQuery *query = [PFQuery queryWithClassName:@"PeopleNames"];
     [query includeKey:@"Name"];
     [query selectKeys:@[@"Name"]];
     [query findObjectsInBackgroundWithBlock:^(NSArray *results, NSError *error) {

     for (PFObject *object in results) {
        [self.boyNames addObject:[object objectForKey:@"Name"]];
    }
}];

推荐答案

[query selectKeys:@[@"Name"]];正确，以将返回的数据限制为仅名称.不需要[query includeKey:@"Name"];，因为它是将目标对象包括在关系的另一端(您没有)的方法.

[query selectKeys:@[@"Name"]]; is correct to limit the returned data to only the names. [query includeKey:@"Name"]; is not required as it is the way to include the destination objects at the other end of a relationship (which you don't have).

因此，保留[query selectKeys:@[@"Name"]];并删除[query includeKey:@"Name"];，您会得到想要的东西.

So, keep [query selectKeys:@[@"Name"]]; and remove [query includeKey:@"Name"]; and you'll get what you want.

这篇关于如何从Parse.com获取单个键的所有值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！