获取xmllint以输出xpath结果\ n分隔，用于属性选择器 [英] Get xmllint to output xpath results \n-separated, for attribute selector

问题描述

如何获取xmllint为属性每行"输出xpath选择器的多个结果?

How can I get xmllint to output multiple results of xpath selector for attributes "per line"?

以这个例子为例:

  <?xml version="1.0" encoding="ISO-8859-1"?>
  <config>
          <tagX key1="value1 " key2=" value2"/>
          <tagY key3="value3" key4=" value4 "/>
  </config>


  $ xmllint example.xml --xpath "/config/*/@*"

结果是:

   key1="value1 " key2=" value2" key3="value3" key4=" value4 "

我想要得到的是:

   key1="value1 "
   key2=" value2"
   key3="value3"
   key4=" value4 "

我是否需要在偶数引号后进行拆分，或者有没有更整洁的方法呢?

Would I need to split after even-numbered quote marks, or is there any neater way to do this?

还有一个相关问题，关于同一主题只是关于挑选<tag>value</tag>而不是<tag attribute="value" />

There's a related question, about the same subject except it's about picking out contents of <tag>value</tag>, and not <tag attribute="value" />

推荐答案

您可以尝试:

$ xmllint --shell inputfile <<< `echo 'cat /config/*/@*'`

不过，您可能需要grep输出，以便过滤掉不需要的行.

You might need to grep the output, though, so as to filter the undesired lines.

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