用Python解析Lisp文件 [英] Parsing a lisp file with Python

问题描述

我有以下lisp文件，该文件来自 UCI机器学习数据库.我想使用python将其转换为平面文本文件.典型的行如下所示:

I have the following lisp file, which is from the UCI machine learning database. I would like to convert it into a flat text file using python. A typical line looks like this:

(1 ((st 8) (pitch 67) (dur 4) (keysig 1) (timesig 12) (fermata 0))((st 12) (pitch 67) (dur 8) (keysig 1) (timesig 12) (fermata 0)))

我想将其解析为一个文本文件，例如:

I would like to parse this into a text file like:

time pitch duration keysig timesig fermata
8    67    4        1      12      0
12   67    8        1      12      0

是否有一个python模块可以智能地对此进行解析?这是我第一次看到Lisp.

Is there a python module to intelligently parse this? This is my first time seeing lisp.

推荐答案

如此答案， pyparsing 似乎是正确的工具:

As shown in this answer, pyparsing appears to be the right tool for that:

inputdata = '(1 ((st 8) (pitch 67) (dur 4) (keysig 1) (timesig 12) (fermata 0))((st 12) (pitch 67) (dur 8) (keysig 1) (timesig 12) (fermata 0)))'

from pyparsing import OneOrMore, nestedExpr

data = OneOrMore(nestedExpr()).parseString(inputdata)
print data

# [['1', [['st', '8'], ['pitch', '67'], ['dur', '4'], ['keysig', '1'], ['timesig', '12'], ['fermata', '0']], [['st', '12'], ['pitch', '67'], ['dur', '8'], ['keysig', '1'], ['timesig', '12'], ['fermata', '0']]]]

出于完整性考虑，这是格式化结果的方式(使用文本表):

For the completeness' sake, this is how to format the results (using texttable):

from texttable import Texttable

tab = Texttable()
for row in data.asList()[0][1:]:
    row = dict(row)
    tab.header(row.keys())
    tab.add_row(row.values())
print tab.draw()

+---------+--------+----+-------+-----+---------+
| timesig | keysig | st | pitch | dur | fermata |
+=========+========+====+=======+=====+=========+
| 12      | 1      | 8  | 67    | 4   | 0       |
+---------+--------+----+-------+-----+---------+
| 12      | 1      | 12 | 67    | 8   | 0       |
+---------+--------+----+-------+-----+---------+

要将数据转换回lisp表示法:

To convert that data back to the lisp notation:

def lisp(x):
    return '(%s)' % ' '.join(lisp(y) for y in x) if isinstance(x, list) else x

d = lisp(d[0])

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