在Python 2.4中使用urllib解析查询字符串 [英] parse query string with urllib in Python 2.4

问题描述

使用Python2.4.5(不要问！)，我想解析一个查询字符串并获得一个dict作为回报.我是否需要像下面这样手动"进行操作?

Using Python2.4.5 (don't ask!) I want to parse a query string and get a dict in return. Do I have to do it "manually" like follows?

>>> qs = 'first=1&second=4&third=3'
>>> d = dict([x.split("=") for x in qs.split("&")])
>>> d
{'second': '4', 'third': '3', 'first': '1'}

在urlparse中找不到任何有用的方法.

Didn't find any useful method in urlparse.

推荐答案

您有两个选择:

>>> cgi.parse_qs(qs)
{'second': ['4'], 'third': ['3'], 'first': ['1']}

或

>>> cgi.parse_qsl(qs)
[('first', '1'), ('second', '4'), ('third', '3')]

cgi.parse_qs()返回的dict中的值是列表而不是字符串，以便处理多次指定相同参数的情况:

The values in the dict returned by cgi.parse_qs() are lists rather than strings, in order to handle the case when the same parameter is specified several times:

>>> qs = 'tags=python&tags=programming'
>>> cgi.parse_qs(qs)
{'tags': ['python', 'programming']}

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