有没有更好的方法来用Python编写此URL操作? [英] Is there a better way to write this URL Manipulation in Python?

问题描述

我很好奇是否有一种更简单的方法可以从网址中删除特定参数.我想到的是以下内容.这似乎有些冗长.欢迎使用库或使用更多pythonic版本.

I'm curious if there's a simpler way to remove a particular parameter from a url. What I came up with is the following. This seems a bit verbose. Libraries to use or a more pythonic version appreciated.

parsed = urlparse(url)
if parsed.query != "":
    params = dict([s.split("=") for s in parsed.query.split("&")])
    if params.get("page"):
        del params["page"]
    url = urlunparse((parsed.scheme,
                      None,
                      parsed.path,
                      None,
                      urlencode(params.items()),
                      parsed.fragment,))
    parsed = urlparse(url)

推荐答案

我创建了一个小的帮助程序类，以结构化的方式表示url:

I've created a small helper class to represent a url in a structured way:

import cgi, urllib, urlparse

class Url(object):
    def __init__(self, url):
        """Construct from a string."""
        self.scheme, self.netloc, self.path, self.params, self.query, self.fragment = urlparse.urlparse(url)
        self.args = dict(cgi.parse_qsl(self.query))

    def __str__(self):
        """Turn back into a URL."""
        self.query = urllib.urlencode(self.args)
        return urlparse.urlunparse((self.scheme, self.netloc, self.path, self.params, self.query, self.fragment))

然后您可以执行以下操作:

Then you can do:

u = Url(url)
del u.args['page']
url = str(u)

有关此内容的更多信息: Web开发中心.

More about this: Web development peeve.

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