在Python中解析TCL列表 [英] Parsing TCL lists in Python

问题描述

例如，我需要在双花括号上分割以空格分隔的TCL列表...例如...

 OUTPUT = """{{172.25.50.10:01:01-Ethernet 172.25.50.10:01:02-Ethernet {Traffic Item 1}}} {{172.25.50.10:01:02-Ethernet 172.25.50.10:01:01-Ethernet {Traffic Item 1}}}"""
 

这应该解析为...

 OUTPUT = ["""{{172.25.50.10:01:01-Ethernet 172.25.50.10:01:02-Ethernet {Traffic Item 1}}}""", 
    """{{172.25.50.10:01:02-Ethernet 172.25.50.10:01:01-Ethernet {Traffic Item 1}}}"""]
 

我尝试过...

 import re
splitter = re.compile('}}\s+{{')
splitter.split(OUTPUT)
 

但是，这会修剪中间的括号...

 ['{{172.25.50.10:01:01-Ethernet 172.25.50.10:01:02-Ethernet {Traffic Item 1}',
'172.25.50.10:01:02-Ethernet 172.25.50.10:01:01-Ethernet {Traffic Item 1}}}']
 

我不知道如何只分割}} {{之间的空格.我知道我可以手动作弊并插入丢失的牙套，但我宁愿找到一种简单的方法来有效地解析出这个括号.

是否可以使用re.split(或其他一些python解析框架)解析OUTPUT来获取任意数量的包含{{content here}}的以空格分隔的行?

解决方案

您可以修改正则表达式以使用肯定的超前/后断言，而不会使用任何字符串:

re.compile('(?<=}})\s+(?={{)')

I need to split space-delimited TCL lists on double braces... for instance...

OUTPUT = """{{172.25.50.10:01:01-Ethernet 172.25.50.10:01:02-Ethernet {Traffic Item 1}}} {{172.25.50.10:01:02-Ethernet 172.25.50.10:01:01-Ethernet {Traffic Item 1}}}"""

This should parse into...

OUTPUT = ["""{{172.25.50.10:01:01-Ethernet 172.25.50.10:01:02-Ethernet {Traffic Item 1}}}""", 
    """{{172.25.50.10:01:02-Ethernet 172.25.50.10:01:01-Ethernet {Traffic Item 1}}}"""]

I have tried...

import re
splitter = re.compile('}}\s+{{')
splitter.split(OUTPUT)

However, that trims the braces in the center...

['{{172.25.50.10:01:01-Ethernet 172.25.50.10:01:02-Ethernet {Traffic Item 1}',
'172.25.50.10:01:02-Ethernet 172.25.50.10:01:01-Ethernet {Traffic Item 1}}}']

I can't figure out how to only split on the spaces between }} {{. I know I can cheat and insert missing braces manually, but I would rather find a simple way to parse this out efficiently.

Is there a way to parse OUTPUT with re.split (or some other python parsing framework) for an arbitrary number of space-delimited rows containing {{content here}}?

解决方案

You could modify your regex to use positive lookahead/behind assertions, which don't consume any of the string:

re.compile('(?<=}})\s+(?={{)')

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