Scala等效于java.util.Scanner [英] Scala equivalent of java.util.Scanner

问题描述

我对将java.util.Scanner与next()，hasNext()，nextInt()，nextLine()等用于解析输入非常熟悉.

I am very familiar with using java.util.Scanner with next(), hasNext(), nextInt(), nextLine(), and the like to parse input.

我应该在Scala中使用其他东西吗?

Is there something else I should use in Scala?

此数据不是根据语法来构造的；比这更特别.

This data isn't structured according to a grammar; it's more ad-hoc than that.

例如，假设我有一个库存.输入的每一行均以名称开头，然后具有这些项目的数量，然后具有这些项目的ID

For example, lets say I had a inventory. Each line of input starts with the name, then has the quantity of those items, then has the ids for those items

Firetruck 2 A450M A451M
Machine 1 QZLT
Keyboard 0 

我看到Console具有诸如readInt()之类的方法，但是它读取了整行输入；似乎不存在nextInt()的等效项.

I see that Console has methods such as readInt(), but that reads an entire line of input; the equivalent of nextInt() doesn't seem to exist.

java.util.Scanner显然可以解决问题.但是我还有其他需要使用的东西(例如，返回Scala而不是Java类型的东西)吗?

java.util.Scanner obviously does the trick. But is there something else I should use (for example, something that returns Scala rather than Java types)?

推荐答案

不存在等效的Scala实现.但是我看不出有什么原因，因为java.util.Scanner可以很好地工作，并且所有java原语类型都将隐式转换为Scala类型.

No there is no equivalent Scala implementation. But I don't see a reason for one as java.util.Scanner would work perfectly fine and all java primitives types would be converted to Scala types implicitly.

例如，对于返回Scala而不是Java类型的东西"，Scanner在scala中使用时将返回scala类型.

So as for "for example, something that returns Scala rather than Java types", Scanner will return scala types when used in scala.

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