如何在没有类的情况下使用BeautifulSoup提取值 [英] How to extract values with BeautifulSoup with no class

问题描述

html代码:

<td class="_480u">
    <div class="clearfix">
        <div>
            Female
        </div>
    </div>
</td>

我希望将值"Female"作为输出.

I wanted the value "Female" as an output.

我尝试了bs.findAll('div',{'class':'clearfix'}); bs.findAll('tag',{'class':'_480u'}) 但是这些类遍布我的html代码，并且输出很大.我想在搜索中合并{td-> class =".."和div-> class =".."}，以便将输出作为Female.我该怎么办?

I tried bs.findAll('div',{'class':'clearfix'}) ; bs.findAll('tag',{'class':'_480u'}) But these classes are all over my html code and the output is a big list. I wanted to incorporate {td --> class = ".." and div --> class = ".."} in my search, so that I get the output as Female. How can I do this?

谢谢

推荐答案

使用 stripped_strings 属性:

>>> from bs4 import BeautifulSoup
>>>
>>> html = '''<td class="_480u">
...     <div class="clearfix">
...         <div>
...             Female
...         </div>
...     </div>
... </td>'''
>>> soup = BeautifulSoup(html)
>>> print ' '.join(soup.find('div', {'class': 'clearfix'}).stripped_strings)
Female
>>> print ' '.join(soup.find('td', {'class': '_480u'}).stripped_strings)
Female

或将类指定为空字符串(或None)并使用string属性:

or specify class as empty string (or None) and use string property:

>>> soup.find('div', {'class': ''}).string
u'\n            Female\n        '
>>> soup.find('div', {'class': ''}).string.strip()
u'Female'

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