c语言:将文件内容读取为数字并将它们加在一起 [英] c language : read file content as numbers and add them together

问题描述

我的文本文件中包含以下内容:values.txt

I have the following in a text file called: values.txt

1 4 
2.5 3.76
122 10
277.543 
165.4432

我正在尝试读取此文本文件的内容，并将每两对加在一起并输出结果... 输出将是这样的:

I am trying to read the content of this text file, and add each two pairs together and output the result ... the output would be something like this :

1 Pair:(1, 4) = 5

2 Pair:(2.5, 3.76)= 6.26

以此类推..

我正在打开这样的文件

int c;
FILE myfile; 

myfile= fopen("values.txt", "r"); 
if ( myfile == NULL ) { 
  printf("Cannot open TEXT file\n");
  return 1; 
}

double aa,bb;
while ( (c = getc(myfile) ) != EOF ) { 
    // HERE SHOULD I DO THE OUTPUT BUT HOW?
}

我们非常感谢您的帮助.

Any help is really appreciated ..

语言= C

推荐答案

以下代码可以实现您所期望的. myfile应该声明为FILE *. fopen返回一个指向FILE结构的指针.如果文件很大，我建议读取大尺寸的缓冲区(例如65535等)，然后按char解析char并将其转换为float值.与处理文本浮点值相比，它减少了系统调用开销，该过程比处理文本花费更多的时间.

The following code does what you expect. myfile should be declared as FILE*. fopen returns a pointer to FILE structure. If the file is very large, I would recommend reading in buffers of big size (eg: 65535 etc) and parse it char by char and convert it to float values. It reduces system call overhead which takes more time than processing text to float values.

#include <stdio.h>
#include <string.h>

main(int argc, char *argv[])
{
    FILE* myfile; 

    myfile = fopen("values.txt", "r"); 
    if ( myfile == NULL ) { 
        printf("Cannot open TEXT file\n");
        return 1; 
    }

    double aa,bb;
    while (2 == fscanf(myfile, "%lf %lf", &aa, &bb)) {
        printf("%lf\n", aa+bb);
    }
    return 0;
}

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