将字符串转换为数字而不会丢失小数 [英] Convert strings to numbers without losing decimals

问题描述

我正在开发地图，我必须将此参数保存在Parse数据库中:

I'm developing a map and I have to save this parameters on Parse database:

纬度:20.6350.长:-103.5334

lat.: 20.6350 . Long: -103.5334

问题是当我将它们转换为数字时，该函数将20.6350转换为20.635. ¿我该怎么做才能使tu保留最后一个零?

The problem is when i convert them into numbers, that function converts 20.6350 to 20.635. ¿What can I do in order tu preserve the last zero?

推荐答案

您应该指定信号图，它们将正确显示.

You should specify the sig figs and they will display properly.

$lat = "20.6350";
$lng = "-103.5334";

print number_format($lat, 4); // 4 sig figs
print number_format($lng, 4);

有关其他格式设置信息，请参见 http://php.net/number_format

See http://php.net/number_format for additional formatting info

更新

根据您上面的评论，看来您要提取的字符串的长度有所不同，对吗?

Based on your comments above, seems the string you're pulling varies in length, correct?

为什么不仅要获取小数点后的信号无花果数量，还要将其用作number_format()中的第二个参数?我敢肯定有一种更合适的处理方式，但是我相信这会起作用.

Why not just get the amount of sig figs after the decimal then use that as the second argument in number_format()? I'm sure there is a more appropriate way to handle, but this would work I believe.

// Calculate sig figs
$length = strlen($lng) - (stripos($lng, '.') + 1);
number_format($lng, $length);

或一行

number_format($lng, strlen($lng) - (stripos($lng, '.') + 1));

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