用于提取月份和年份的Python正则表达式 [英] Python regular expression for extracting month and year

问题描述

我想从字符串中提取月份和年份.例如:

I want to extract month and year from string. For example:

如果我有字符串From August 2017 - September 2018，则应该将'August 2017'和'September 2018'分为两组.我尝试了以下方法:

If I have a string From August 2017 - September 2018 then I should get 'August 2017' and 'September 2018' as two groups. I tried the following:

import re

regex = r'(\b\d{1,2}\D{0,3}\b-)?\b(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|(Nov|Dec)(?:ember)?)\D?(\d{1,2}\D?)?\D?((19[7-9]\d|20\d{2})|\d{2})'
experience = re.findall(regex, 'August 2017 - Sep 2018')
print(experience)

这将返回[('', '', '20', '17', ''), ('', '', '20', '18', '')]

我还尝试了 re.search :

import re

regex = r'(\b\d{1,2}\D{0,3}\b-)?\b(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|(Nov|Dec)(?:ember)?)\D?(\d{1,2}\D?)?\D?((19[7-9]\d|20\d{2})|\d{2})'
experience = re.search(regex, 'August 2017 - Sep 2018')
print(experience.group())

这仅返回August 2017

我们可以使用一些正则表达式来提取两个日期吗?

Can we have some regex to extract both the dates?

推荐答案

您的意思是这样吗? Regex演示.

Do you mean like this? Regex demo.

import re

string = "From August 2017 - September 2018"
month = re.search("(?P<fmonth>\w+.\d+)\s+\-\s+(?P<smonth>\w+.\d+)", string)
month = month.groups()

print (month)

输出:

('August 2017', 'September 2018')

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