将时间解析到日历中而不丢失日期部分 [英] Parse Time into Calendar without losing Date part

问题描述

我需要在一个Calendar Java对象中存储一个日期/时间，该日期/时间包括今天的日期以及从一个以HH:mm:ss格式的字符串解析的时间.

I need to store in a Calendar Java object a date/time consisting of today's date plus a time parsed from a string in a HH:mm:ss format.

我尝试创建一个新的GregorianCalendar并使用setTime()对其进行初始化，并调用SimpleDateFormat的parse()方法，但随后我发现parse()返回一个Date对象，该对象带有正确的解析时间，但日期为1970年1月1日.

I tried creating a new GregorianCalendar and using setTime() to initialize it with the result of calling a SimpleDateFormat's parse() method but then I noticed that parse() returns me a Date object with the correct parsed time but with the date of Jan 1, 1970.

例如:

String time = "23:32";
String timeFmt = new SimpleDateFormat("HH:mm");
Calendar todaysTime = new GregorianCalendar();

todaysTime.setTime(timeFmt.parse(time));
System.out.println(todaysTime.getTime());

打印:Thu Jan 01 11:32:00 CST 1970 我所期望的是:Wed 03 11:32:00 CST 2015

Prints: Thu Jan 01 11:32:00 CST 1970 What I expected was: Wed 03 11:32:00 CST 2015

我只能看到一种选择:用今天的日期创建第二个GregorianCalendar，然后通过setYear()，setMonth()和setDayOfMonth()手动将年，月和日设置为todaysTime，但我希望有一种更优雅的方法.

I can only see one alternative: Create a second GregorianCalendar with todays date and then set the year, month and day manually into todaysTime via setYear(), setMonth() and setDayOfMonth() but I hope there is a more elegant way to do that.

您能帮我寻找一种更好的方法来解析解析为Date对象的时间部分而又不丢失日期部分吗?

Can you help me look for a better way to parse the time part parsed into a Date object without losing the date part?

推荐答案

您可以执行以下操作:

Date parsedDate = SimpleDateFormat.getInstance().parse(time);
Calendar instance = Calendar.getInstance();
instance.setTime( parsedDate );

Calendar result = Calendar.getInstance();
result.set( Calendar.HOUR_OF_DAY, instance.get( Calendar.HOUR_OF_DAY ) );
result.set( Calendar.MINUTE, instance.get( Calendar.MINUTE ) );

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