在Java中，如何解析大于int大小的字符串 [英] In Java, how do I parse a string bigger than int size

问题描述

我有一个大于2,147,483,647的字符串，我需要解析它. Integer.parseInt不能执行任务，它会引发异常.

I have a string bigger than 2,147,483,647 and I need to parse it. Integer.parseInt doesn't do they job, it throws an exception.

推荐答案

Integer.parseInt 无法完成工作，除非您很乐意丢失数据.在这里考虑您的要求.

Integer.parseInt couldn't do the job, unless you were happy to lose data. Think about what you're asking for here.

尝试 Long.parseLong(String) 或 new BigInteger(String) 表示真正的大整数.

Try Long.parseLong(String) or new BigInteger(String) for really big integers.

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