如何在bash中获取给定路径的根目录? [英] How-To get root directory of given path in bash?

问题描述

我的脚本:

    #!/usr/bin/env bash
    PATH=/home/user/example/foo/bar
    mkdir -p /tmp/backup$PATH

现在我想获取"$ PATH"的第一个文件夹:/home/

And now I want to get first folder of "$PATH": /home/

    cd /tmp/backup
    rm -rf ./home/
    cd - > /dev/null

如何始终像上面的示例一样检测第一个文件夹? "dirname $ PATH"仅返回"/home/user/example/foo/".

How can I always detect the first folder like the example above? "dirname $PATH" just returns "/home/user/example/foo/".

提前谢谢！ :)

推荐答案

我找到了一个解决方案:

I've found a solution:

    #/usr/bin/env bash
    DIRECTORY="/home/user/example/foo/bar"
    BASE_DIRECTORY=$(echo "$DIRECTORY" | cut -d "/" -f2)
    echo "#$BASE_DIRECTORY#";

这总是返回第一个目录.在此示例中，它将返回以下内容:

This returns always the first directory. In this example it would return following:

    #home#

感谢@condorwasabi与awk的想法！ :)

Thanks to @condorwasabi for his idea with awk! :)

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