如何根据特定表达式将字符串列表保存在子列表中? [英] How to save a list of string in sublists according specific expression?
问题描述
我正在做一个脚本来将读取路径保存在子列表中.假设我在一个列表中保存了400个文件路径,每个路径都有特定的语法Ci_whaterver.csv
,然后在我的路径列表中我有这样的内容:
I'm doing a script to save a read path in sublist. Let's suppose I have 400 file paths saved in a list, every path has the specific syntax Ci_whaterver.csv
, then in my pathlist I have something like this:
pathlist=[C1_01.csv,C1_02.csv,...,Cn_01.csv,Cn_02.csv]
在这种情况下,我最终希望订购pathlistf
或进行排序:
I would like to have finally a pathlistf
ordered or sort with this situation:
pathlistf=[[C1_01.csv,C1_02.csv,...],[C2_01.csv,C2_02.csv,...],...,[Cn_01.csv,Cn_02.csv,...]]
我不知道如何重新排序这种方式.
I don't have idea to reorder the path to this way.
您好,我遇到了这个问题:
我想问一个与过去的情况非常相似的事情,假设我走了下一条路:
path=[case1_Qxxx_cap1_whatever.csv,case1_Qxxx_cap1_whatever2.csv,case1_Qxxx_cap1_whatever3.csv,....,case1_Qxxx_cap2_whatever.csv,case1_Qxxx_cap2_whatever2.csv,case1_Qxxx_cap2_whatever3.csv,case2_Qxxx_cap1_whatever.csv,case2_Qxxx_cap1_whatever2.csv,...,case2_Qxxx_cap2_whatever.csv,case2_Qxxx_cap2_whatever2.csv]
Hello again, i got this problem:
I would like to ask something very similar to the past case, let suppose i have the next path:
path=[case1_Qxxx_cap1_whatever.csv,case1_Qxxx_cap1_whatever2.csv,case1_Qxxx_cap1_whatever3.csv,....,case1_Qxxx_cap2_whatever.csv,case1_Qxxx_cap2_whatever2.csv,case1_Qxxx_cap2_whatever3.csv,case2_Qxxx_cap1_whatever.csv,case2_Qxxx_cap1_whatever2.csv,...,case2_Qxxx_cap2_whatever.csv,case2_Qxxx_cap2_whatever2.csv]
我想要这个:
pathf=[[[case1_Qxxx_cap1_whatever.csv,case1_Qxxx_cap1_whatever2.csv,...],[case1_Qxxx_cap2_whatever.csv,Qxxx_cap2_whatever2.csv,...]],[[case2_Qxxx_cap1_whatever.csv,case2_Qxxx_cap1_whatever2.csv,...],[case2_Qxxx_cap2_whatever.csv,case2_Qxxx_cap2_whatever2.csv,...]]]
推荐答案
一种方法是创建字典,并使用部分Ci
作为键,并且以Ci
开头的文件名列表将为该值.例如,使用pathlist = ['C1_01.csv','C1_02.csv', 'C2_01.csv' , 'C3_01.csv', 'C2_02.csv']
,然后我们将创建一个字典来存储
One way will be to create a dictionary and use the part Ci
as key and lists of file names starting with Ci
will be the value. For example, take pathlist = ['C1_01.csv','C1_02.csv', 'C2_01.csv' , 'C3_01.csv', 'C2_02.csv']
, then we will create a dictionary which will store
{'C1': ['C1_01.csv', 'C1_02.csv'], 'C2': ['C2_01.csv', 'C2_02.csv'], 'C3': ['C3_01.csv']}
这是代码:
pathlist = ['C1_01.csv','C1_02.csv', 'C2_01.csv' , 'C3_01.csv', 'C2_02.csv']
d = {}
for path in pathlist:
if path[:2] not in d:
d[path[:2]] = [path]
else:
d[path[:2]].append(path)
pathlistf = []
for key in d:
pathlistf.append(d[key])
print(pathlistf)
# Output: [['C1_01.csv', 'C1_02.csv'], ['C3_01.csv'], ['C2_01.csv', 'C2_02.csv']]
希望这可以解决问题.随时提出任何疑问.
Hope this solves the problem. Feel free to ask any doubt.
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