如何在PHP调用的函数中获取调用文件的绝对路径? [英] How to get the absolute path of the calling file in a function that's called in PHP?

问题描述

在file.php中:

call()...

如何在call()内部获取file.php的绝对路径?

How to get absolute path of file.php inside call() ?

请注意call()可能在另一个文件中定义.

Pay attention that call() may be defined in another file.

another.php:

function call(){..}

file.php:

include(path_to_another.php);
call();

推荐答案

除了 debug_backtrace

function whatever() {
    $t = debug_backtrace();
    echo "called from {$t[0]['file']}";
}

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