Python os.path.commonprefix-是否存在面向路径的函数? [英] Python os.path.commonprefix - is there a path oriented function?

问题描述

所以我有这个python代码:

So I have this python code:

print os.path.commonprefix([r'C:\root\dir',r'C:\root\dir1'])

实际结果

C:\root\dir

所需结果

C:\root

问题1

基于os.path.commonprefix文档:
返回最长路径前缀(按字符输入)

Question 1

Based on os.path.commonprefix documentation:
Return the longest path prefix (taken character-by-character)

是否存在类似的功能:
返回最长路径前缀(由dir获取的dir )

Is there a similar function that:
Return the longest path prefix (taken dir by dir)

如果commonprefix是在os.path中实现的，为什么它不是面向路径的，这意味着返回我想要的结果而不是真实的结果?

if commonprefix is implemented in os.path why isn't it path oriented, meaning return my desired result and not the real one?

我可以自己轻松实现此功能，但是如果已经实现，为什么不使用它呢?

I can implement this easily by myself but if it is already implemented why not using it?

推荐答案

有面向路径的功能吗?

is there a path oriented function?

否，是的. commonprefix()可以处理任意序列，而不仅仅是字符串.

no and yes. commonprefix() can work with arbitrary sequences, not just strings.

将路径拆分为多个组件，然后在其上调用commonprefix():

Split the path into components and call commonprefix() on that e.g.:

>>> import os
>>> from pathlib import PureWindowsPath
>>> a, b = map(PureWindowsPath, [r'C:\root\dir', r'C:\root\dir1'])
>>> PureWindowsPath(*os.path.commonprefix([a.parts, b.parts]))
PureWindowsPath('C:/root')

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